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Leto [7]
3 years ago
12

7.3 Code Practice edhesive

Computers and Technology
2 answers:
sladkih [1.3K]3 years ago
5 0

Answer:

def print_sum(a,b,c):

 print(a+b+c)

one = int(input("Enter the 1st number: "))

two = int(input("Enter the 2nd number: "))

three = int(input("Enter the 3rd number: "))

print_sum(one,two,three)

Explanation:

hope this helped :)

Margaret [11]3 years ago
4 0

Answer:

def print_sum(a,b,c):

print(a+b+c)

one = int(input("Enter the 1st number: "))

two = int(input("Enter the 2nd number: "))

three = int(input("Enter the 3rd number: "))

print_sum(one,two,three)

Explanation:

Hoped this Helped!

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Read 2 more answers
Which threat hunting technique is best suitable when handling datasets that creates limited number of results
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Answer:

Stacking

Explanation:

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3 0
3 years ago
Some numbers are formed with closed paths. the digits 0, 4, 6 and 9 each have 1 closed path and 8 has 2. None of the other numbe
postnew [5]

Answer:

def cal(n):

s=0

while n>0:

r=n%10

if(r==0 or r==4 or r==6 or r==9):

s=s+1

elif r==8:

s=s+2

n=n//10

print(s)

n=int(input("enter number:"))  

print(n)

cal(n)

Explanation:

  • Create a function to calculate count of closed path .
  • Create a variable to store count of closed path .
  • While number is positive , extract last digit of n .
  • Reduce number by truncating last digit .
  • Make a function call to compute count of path.
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