Lizzie has 18 dimes and 12 quarters
<em><u>Solution:</u></em>
Let "d" be the number of dimes
Let "q" be the number of quarters
We know that,
value of 1 dime = $ 0.10
value of 1 quarter = $ 0.25
Given that LIzzie has 30 coins
number of dimes + number of quarters = 30
d + q = 30 ---- eqn 1
Also given that the coins total $ 4.80
number of dimes x value of 1 dime + number of quarters x value of 1 quarter = 4.80
0.1d + 0.25q = 4.8 ------ eqn 2
Let us solve eqn 1 and eqn 2
From eqn 1,
d = 30 - q ---- eqn 3
Substitute eqn 3 in eqn 2
0.1(30 - q) + 0.25q = 4.8
3 - 0.1q + 0.25q = 4.8
0.15q = 1.8
<h3>q = 12</h3>
From eqn 3,
d = 30 - 12
<h3>d = 18</h3>
Thus she has 18 dimes and 12 quarters
Answer:
5/3 or 1.67
Step-by-step explanation:
Find the slope of the original line
3x+5y=4 Subtract 3x from both sides
5y = - 3x + 4 Divide both sides by 5
y = (-3/5)x + 4
The original line has a slope of - 3/5 or - 0.6
Find the slope of the perpendicular line
m1 * m2 = - 1
m1 = - 3/5
m2 = -1/(-3/5)
m2 = 5/3
The slope of the perpendicular line is
5/3 or 1.67
<em>hope </em><em>it</em><em> helps</em>
Answer:
32
Step-by-step explanation:
We can either add all the terms.
2+6=8
2,8
8+6=14
2,8,14
14+6=20
2,8,14,20
20+6=6
2,8,14,20,26
26+6=32
2,8,14,20,26,32
The Sixth term is 32
or We can multiply 6 times 5 (30) and add 2, which would give us 32.
The reasoning behind this is that we are adding six five times (so six times five) and we are also adding the first term (2).
