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3 years ago

How many 3-person committees can be formed in a club with 8 members??

Mathematics

1 answer:

earnstyle [38]3 years ago

7 0

=8C3
=8!/(3!*5!)
=56 ways

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What is the unit rate of 1.49 for 10

kap26 [50]

If you mean it costs $1.49 to buy 10 items, then the unit rate is $0.15 or 15 cents

This is because you divide 1.49 over 10 like so: 1.49/10 = 0.149, then round this to the nearest penny to get 0.15

0.15 dollars = 15 cents

so basically whatever this item is, it costs 15 cents per item

7 0

3 years ago

Read 2 more answers

Which of these statements best describes the relation shown in Item 1?

Misha Larkins [42]

Answer:

It is a many-to-one relation

Step-by-step explanation:

Given

See attachment for relation

Required

What type of function is it?

The relation can be represented as:

$\left[\begin{array}{c}x\\ \\-5\\-2\\1\\5\end{array}\right]$ $\left[\begin{array}{c}y\\ \\10\\11\\4\\10\end{array}\right]$

Where

$x = domain$ and $y = range$

Notice that the range has an occurrence of 10 (twice)

i.e.

$(x_1,y_1) = (-5,10)$ and $(x_2,y_2) = (5,10)$

In function and relations, when two different values in the domain point to the same value in the range implies that, <em>the relation is many to one.</em>

8 0

3 years ago

F^-1(-10) + f(-6) <br> Please help!!!!

Brums [2.3K]

Answer:

-10/f-6f

Step-by-step explanation:

simplify it the equation

4 0

3 years ago

Vincent borrowed $500 from Mitchell for six months how much interest will Michelle earn if he charges Vincent a simple interest

kow [346]

Michelle will earn $15 from the interest rate.

5 0

3 years ago

TIMED QUESTION NEED HELP FASTWhat values of b satisfy 3(2b + 3)2 = 36?

egoroff_w [7]

Answer:

$\frac{-3+ 2\sqrt{3}}{2}\textrm{ and }\frac{-3- 2\sqrt{3}}{2}$

Step-by-step explanation:

$3(2b+3)^{2}=36\\\frac{3(2b+3)^{2}}{3}=\frac{36}{3}\\(2b+3)^{2}=12$

Taking square root both sides, we get

$\sqrt{(2b+3)^{2}}=\pm \sqrt{12}\\2b+3=\pm \sqrt{4\times 3}\\2b+3=\pm 2\sqrt{3}\\2b+3-3=\pm 2\sqrt{3}-3\\2b=-3\pm 2\sqrt{3}\\b=\frac{-3\pm 2\sqrt{3}}{2}\\b=\frac{-3+ 2\sqrt{3}}{2}\textrm{ or }b=\frac{-3- 2\sqrt{3}}{2}$

Therefore, the values of $b$ are:

$\frac{-3+ 2\sqrt{3}}{2}\textrm{ and }\frac{-3- 2\sqrt{3}}{2}$

5 0

3 years ago

Read 2 more answers