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kotykmax [81]
3 years ago
11

Al cruzar una ´planta de arveja de flores purpura con otra de flores blancas mendel obtuvo una f1 formada por las plantas de flo

res purpuras. La f2 estaba formada por plantas
Biology
1 answer:
anastassius [24]3 years ago
7 0

Answer:

F2:

-75% plantas con flores púrpuras

- 25% plantas con flores blancas

Explanation:

La F1 de un cruzamiento entre líneas puras para un rasgo dominante monogénico (en este caso, color de la flor) es siempre igual al fenotipo para el carácter dominante (en este caso, plantas con flores púrpuras). En este ejemplo, el alelo dominante que codifica para el color púrpura enmascara la expresión del alelo recesivo (flores blancas) en plantas F1 heterocigotas. Por otra parte, el cruzamiento entre plantas F1 con genotipo heterocigoto producirá una F2 con una proporción fenotípica 3:1 (es decir, 3 plantas con fenotipo dominante por cada planta con fenotipo recesivo), lo cual es igual a un 75% de plantas con fenotipo dominante (tres plantas: una con genotipo homocigota dominante y 2 con genotipo heterocigoto) y un 25% de plantas con fenotipo recesivo (una planta con genotipo homocigota recesivo). Esto sucede porque los alelos dominante y recesivo responsables del color de la flor segregan independientemente durante la formación de los gametos en plantas F1 heterocigotas.

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