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2 years ago

Weekly wages at a certain factory

Mathematics

1 answer:

shtirl [24]2 years ago

6 0

Where is the question

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Derek says that the quotient of -2/7 divided by -2/21 is -1/3. Part A: What is the correct quotient? Part B: What mistake did De

Thepotemich [5.8K]

Answer:

The correct quotient is 3.

I think Derek has mistaken to divide $-\frac{2}{21}$ by $\frac{2}{7}$ .

Step-by-step explanation:

We have to check the quotient of $(-\frac{2}{7}) \textrm{ divided by }(-\frac{2}{21})$ .

Part A:

Now, $(-\frac{2}{7}) \textrm{ divided by }(-\frac{2}{21})$ .

= $\frac{-\frac{2}{7} }{-\frac{2}{21} } =3$

So, the correct quotient is 3.

Part B:

Derek says that the quotient is $-\frac{1}{3}$ .

So, I think Derek has mistaken to divide $-\frac{2}{21}$ by $\frac{2}{7}$ . (Answer)

8 0

2 years ago

Given that sin0=21/29 what is the value cos 0 for 0°< 0<90°

sp2606 [1]

Answer:

20/29

Step-by-step explanation:

sin θ = 21/29

Use Pythagorean identity:

sin² θ + cos² θ = 1

(21/29)² + cos² θ = 1

441/841 + cos² θ = 1

cos² θ = 400/841

cos θ = ±20/29

Since 0° < θ < 90°, cos θ > 0. So cos θ = 20/29.

3 0

2 years ago

Please say the balance

Misha Larkins [42]

Answer:

750.64

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers

If the ratio of corresponding segments is 2:3, then the ratios of the areas and volumes are

kobusy [5.1K]

Answer:

4:9

Step-by-step explanation:

Area is squaring and Volume is cubing

So it'd be 2^2:3^3, or 4:9

I hope this helped and have a good rest of your day!

6 0

2 years ago

Find the area of a compound shape<br><br> Can you please explain

gtnhenbr [62]

Answer:

$A=292.53~m^2$

Step-by-step explanation:

<u>Area of a Compound Shape</u>

The shape shown in the image is made of two shapes: Half a circle of radius 8 m and a triangle of base 24 m and height 16 m.

The area of a circle of radius r is:

$A_c = \pi r^2$

The area of a triangle of base b and height h is:

$\displaystyle A_t=\frac{b.h}{2}$

Calculate the area of the circle:

$A_c = \pi 8^2$

$A_c = 64\pi$

Area of half the circle:

$A_c/2 = 32\pi~m^2$

Area of the triangle:

$\displaystyle A_t=\frac{24\cdot 16}{2}$

$A_t=192~m^2$

The area of the shaded shape is:

$A=32\pi~m^2+192~m^2$

Substituting the value of pi:

$\mathbf{A=292.53~m^2}$

4 0

2 years ago