Answer:

Explanation:
You need to find the probability that exactly three of the first 11 inspected packages are damaged and the fourth is damaged too.
<u>1. Start with the first 11 inspected packages:</u>
a) The number of combinations in which 11 packages can be taken from the 20 available packages is given by the combinatory formula:


b) The number of combinations in which 3 damaged packages can be chossen from 7 damaged packages is:

c) The number of cominations in which 8 good packages can be choosen from 13 good pacakes is:

d) The number of cominations in which 3 damaged packages and 8 good packages are chosen in the first 11 selections is:

e) The probability is the number of favorable outcomes divided by the number of possible outcomes, then that is:

Subsituting:


<u>2. The 12th package</u>
The probability 12th package is damaged too is 7 - 3 = 4, out of 20 - 11 = 9:
<u>3. Finally</u>
The probability that exactly 12 packages are inspected to find exactly 4 damaged packages is the product of the two calculated probabilities:

If you are meaning Percent... (which I believe you are) .8 is the same as .80, and for percent, take away the decimal and put a percent sign next to it. your answer is 80%
Consider the given equation:

Cross multiplying in the given equation, we get

Applying distributive property which states
, we get


Adding '4' on both the sides, we get


Subtracting '10n' from both the sides of the equation, we get


Dividing by '-8' in both the sides of the equation, we get

Therefore, the value of 'n' is -1.
X is the smaller number. 3x + 15 is the larger number. So x + 3x + 15 = 63. 4x + 15 = 63.
4x = 48. x = 12. (Smaller number) The larger 36 + 15 or 51.