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3 years ago

Solve the system of equations Y=5x+12 X=4y+15

Mathematics

1 answer:

madam [21]3 years ago

3 0

Y +x is 56 so that means the answer is 56

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10 binder; 60% off; 6% tax

laila [671]

Answer:

I'm going to assume that the binder is $10, and that the tax is applied after the 60% off, in which case the answer is $4.24

Step-by-step explanation:

10 * 10 = 100

6 * 10 = 60

10 - 6 = 4

6 / 25 = 0.24

4 + 0.24 = 4.24

Answer: $4.24

4 0

3 years ago

The accounting department at Nagata Glass reimbursed Abba Jay for traveling to two sales presentations in New Orleans this month

Yuliya22 [10]

The answer is $122.13

Explanation:

610 • 0.32 = 1,105.6

Then you’re going to add everything up:

650 + 260.40 + 260.40 + 16.95 + 11.56 + 10.56 + 17.84

And get =

1,227.73

And you’re going to subtract that with 1,105.6 and get the answer.

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3 years ago

What is the answer when you evaluate

Paha777 [63]

Answer:

The answer is 17

Step-by-step explanation:

To find the answer, we first have to put the values in for a and b.

√225 + ║2 - 3(1/3)(4)║

√225 + ║2 - 4║

√225 + ║-2║

√225 + 2

15 + 2

5 0

3 years ago

Solve each inequality graphically.<br><br>|x-3|-2>-1

Nutka1998 [239]

Answer:

•this is axample

•what the number

•|x-3|-2>-1

Step-by-step explanation:

<h2>#CarryOnLearning</h2>

4 0

3 years ago

The total number of people at a football game was 5600. Field-side tickets were 40 dollars and end-zone tickets were 20 dollars.

rewona [7]

Answer:

1100 field-side tickets and 4500 end-zone tickets.

Step-by-step explanation:

Let x represent number of field side tickets and y represent number of end-zone tickets.

We have been given that the total number of people at a football game was 5600. We can represent this information in an equation as:

$x+y=5600...(1)$

$y=5600-x...(1)$

We are also told that Field-side tickets were 40 dollars and end-zone tickets were 20 dollars.

Cost of x field side tickets would be $40x$ and cost of y end-zone tickets would be $20y$ .

The total amount of money received for the tickets was $134000. We can represent this information in an equation as:

$40x+20y=134000...(2)$

Upon substituting equation (1) in equation (2), we will get:

$40x+20(5600-x)=134000$

$40x+112000-20x=134000$

$20x+112000=134000$

$20x+112000-112000=134000-112000$

$20x=22000$

$\frac{20x}{20}=\frac{22000}{20}$

$x=1100$

Therefore, 1100 field side tickets were sold.

Upon substituting $x=1100$ in equation (1), we will get:

$y=5600-1100$

$y=4500$

Therefore, 4500 end-zone tickets were sold.

3 0

3 years ago