On a number line what nomber is 3 units to the left of 3
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Graph the boundary line of y = 3x + 4 first. This is pretty easy. I'll give the steps below.
1. plot the y intercept: we see from the equation, the y intercept is 4 or specifically the point (0,4).... plot this as your first point.
2. Use the slope to get another point or couple of points. We can see from the equation that the slope is 3(the coefficient of 'x') and can be represented as a fraction
This fraction implies that you would move up three units of space and to the right 1 unit of space from the y intercept to get to your next point.
3. Draw a broken or dashed line through these two points due to the type of inequality symbol you have in the original problem(a less than symbol). This means the points that lie on this line will not actually by solutions.
4. Now that you have the boundary line sketched, all the points falling below the boundary line will be the solutions to the inequality <span>Y<3x+4 So shade that region of your graph.
5. To prove this, you can test the point (0,0) as follows: 0</span><span><3(0)+4
or, 0</span><4 which is a true statement, meaning the point (0,0) is a solution as well as all other points on that side of the boundary line.
Good luck ,, and I hope this helped.
1. plot the y intercept: we see from the equation, the y intercept is 4 or specifically the point (0,4).... plot this as your first point.
2. Use the slope to get another point or couple of points. We can see from the equation that the slope is 3(the coefficient of 'x') and can be represented as a fraction
3. Draw a broken or dashed line through these two points due to the type of inequality symbol you have in the original problem(a less than symbol). This means the points that lie on this line will not actually by solutions.
4. Now that you have the boundary line sketched, all the points falling below the boundary line will be the solutions to the inequality <span>Y<3x+4 So shade that region of your graph.
5. To prove this, you can test the point (0,0) as follows: 0</span><span><3(0)+4
or, 0</span><4 which is a true statement, meaning the point (0,0) is a solution as well as all other points on that side of the boundary line.
Good luck ,, and I hope this helped.
