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goldenfox [79]
3 years ago
7

Solve for x. A. 2 B. 5 C. 0 D. 7

Mathematics
1 answer:
Agata [3.3K]3 years ago
4 0

Answer:

We know that the angle which lineer and divided by |AB| equal to 130°

Step-by-step explanation:

if 130° look at the 2x+260 we can say that 2x+260=260° so X equal to Zero (0)

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Rectangle w/area of 91 has dimensions of (x+2) and (2x+3). Solve for dimensions.
Leviafan [203]

Answer:

5unit

Step-by-step explanation: since area of rectangle = length*width

Here length is (x+2) and width is(2x+3)

(x+2)(2x+3)=91

On further solving

2x^2+75x-85=0

2x^2-10x+17x-85=0

2x(x-5)+17(x-5)=0

(2x+17)(x-5)=0

x=5unit

8 0
3 years ago
Plz help with these first one gets brainliest
vlabodo [156]

Answer:

A=(1,6) B=(1,6)

Step-by-step explanation:

Its the absolotle value between them.

4 0
3 years ago
Read 2 more answers
If P and Q are two sets then n( P-Q) means ?
Lapatulllka [165]

\huge{\mathbb{ \tt{ANSWER}}}

I shall use the symbol U for union

^ for intersection

~ for complement

<h3 /><h3>----------------------------------------------------------------------------------------------------</h3>

The property of set subtraction states that for any sets X and Y, X-Y = X ^ Y~

That is in words, X throw away Y is the same as the intersection of X and the complement of Y

or X and anything NOT in Y

At the SET level, the proof looks like this:

(P-Q) U (Q-P) = « given

(P^Q~) U (Q ^ P~) = « property of set subtraction

(P U Q) ^ (P U P~) ^ (Q~ U Q) ^ (Q~ U P~) = « distributive property

(P u Q) ^ (Q~ U P~) = « Union of any set with it's complement is the universal

set which gets dropped by any intersection of a non-universal set

(P u Q ) ^ (Q ^ P)~ = « De Morgan's Law

(P u Q) - (Q ^ P) = « property of set subtraction

(P u Q) - (P ^ Q) « commutative property

<h3>----------------------------------------------------------------------------------------------------</h3>

At the ELEMENT level, the proof looks like this:

» Proves left side is subset of right side

If x is in (P-Q) U (Q-P) then x is in (P-Q) OR x is in (Q-P)

If x is in P-Q then x is in P but not in Q.

Then X is in P U Q.

Since x is not in Q, x is NOT in P ^ Q

Hence x is in P U Q but NOT in P^Q, which

means it is an element if (P U Q) - (P ^ Q)

Therefore x is an element of the set defined by the right side, which means (P-Q) U (Q-P) is a subset of (P U Q) - (P ^ Q)

« proves right side is subset of the left side

If x is an element of (P U Q) - (P ^ Q) then

x is in (P U Q) but NOT in (P^Q)

Since x is in P U Q, x is in P OR x is in Q.

Since x is NOT in (P^Q) then x is NOT in BOTH P and Q.

Hence x is in either P or Q but not both.

If x is in P, then x is not in Q, so x is in P-Q.

Therefore x is in (P-Q) U (Q-P).if x is in Q, then x is not in P, so x is in Q-P.Therefore x is in (Q-P) U (P-Q).There x is an element of set defined by the left side, which menas (P u Q)-(P ^Q) is a subset of (P-Q) U (Q-P).

#CarryOnLearning

#LetsEnjoyTheSummer

<h3><u>»<em>X</em><em> </em></u><em><u>x</u></em><em><u> </u></em><em><u>K</u></em><em><u> </u></em><em><u>i</u></em><em><u> </u></em><em><u>m</u></em><em><u> </u></em><em><u>0</u></em><em><u> </u></em><em><u>2</u></em><em><u> </u></em><em><u>x</u></em><em><u> </u></em><em><u>X</u></em></h3>
8 0
3 years ago
HELP HELP PLEASE DUE TONIGHT
Serjik [45]

Answer:

Gurl... I GOT CHU!!

Step-by-step explanation:

1. x = -9

2. y = -42

3. x = -15

4. z = 15

5. x = -3

Here ya go!!

7 0
4 years ago
Over a 14 day period , Jamal went to the store 5 times . Based on this information, which statement best describes how many time
ella [17]
12 or 13 times because 14 days is 2 weeks for 2x5=10 so that’s 4 weeks add 1 more week so I think 12
5 0
3 years ago
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