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Naddika [18.5K]
3 years ago
7

Color in poison dart frogs is controlled by a single gene with multiple alleles. A blue poison dart frog that is heterozygous fo

r the blue allele (Cb) and red allele (Cr) is crossed to a yellow poison dart frog that is heterozygous for the orange (Co) and yellow (Cy) alleles. Their progeny are 1/2 blue, 1/4 orange, and 1/4 yellow. Determine the order of dominance for the alleles. (Order of dominance is indicated as: A > B > C > D such that A is dominant over all alleles, B is dominant over C and D, C is dominant only to D, and D is recessive to all alleles.)
Biology
1 answer:
8_murik_8 [283]3 years ago
7 0

Answer:

Cb>Cy>Co>Cr

Explanation:

First of al we need to do the Punnett square. As a result we get the genotypes:

CyCb

CyCr

CoCb

CoCr

Because there are no red frogs, red is the least dominant as it isn't expressed in any genotype.

Half of the progeny are blue and half of the possible genotypes contain the blue allele meaning that blue is expressed in all genotypes. This means that blue is the most dominant.

The only alleles left are yellow and orange. We can deduce that yellow is more dominant than orange because one of the parent frogs is yellow and contains the genes for yellow and orange.

As a result blue is the most dominant, yellow is the second most dominant, orange is the third most dominant and red is the least dominant.

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The lac operon can be regulated by two distinct methods. Which of the following statements are correct?The lac operon can be act
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Answer:

  • The lac operon can be activated by the binding of allolactose to the repressor protein, releasing it from DNA and thereby allowing for transcription to occur.
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Explanation:

Lactose operon or lac operon  (includes lacZ, lacY and lacA genes) is found in some bacteria and the products of its genes are involved in lactose metabolism. So, this operon is active (genes are transcribed) when lactose is present and glucose is absent (or at low level). The operon is regulated by the lac repressor which acts as a lactose sensor and catabolite activator protein (CAP) which acts as a glucose sensor.

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In humans, blue eyes are inherited as a recessive autosomal trait and color blindness is an X-linked recessive trait. A woman wi
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Answer:

A) One-half of their daughters will have normal color vision and brown eyes; 1/2 of their daughters will have normal color vision and blue eyes.

Explanation:

<u>The genotypes and phenotypes are</u>:

  • BB or Bb= brown eyes
  • bb= blue eyes
  • XᴰXᴰ, XᴰXᵈ (women) or XᴰY (men)= normal vision
  • XᵈXᵈ (women) or XᵈY (men) = color blind

A woman has blue eyes (bb) and normal color vision (she has an Xᴰ chromosome) but her father was color-blind, so the other X chromosome she has carries the recessive d allele. She has the genotype bb XᴰXᵈ.

The man has normal color vision (he is XᴰY) and has brown eyes, but his mother had blue eyes so he must have inherited a b allele from her and is therefore heterozygous Bb. His genotype is BbXᴰY.

The blue/brown eyes gene is autosomal and independent from the sex-linked color blindness gene.

The woman can produce the gametes b Xᴰ and b Xᵈ.

The man can produce the gametes B Xᴰ, b Xᴰ, B Y and bY.

<u />

<u>The female daughters can have the following genotypes and phenotypes:</u>

  • Bb XᴰXᴰ brown eyes, normal color vision
  • Bb XᴰXᵈ brown eyes, normal color vision
  • bb Xᴰ Xᴰ blue eyes, normal color vision
  • bb Xᴰ Xᵈ blue eyes, normal color vision

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Answer: b. zero percent

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