We need to find a polynomial function f(x) with degree 3 and zeros 2 and 2i, such that:

Since 2i is a zero, -2i is also a zero of this function. Thus, we have:

where a is a constant.
Expanding the expression on the right side, we obtain:

Now, using f(-1) = 30, we obtain:

Therefore, the function is:
Answer
Answer:
x = 8
Step-by-step explanation:
6 = 14 - x
chance the equation around so it is solvable
14 - x = 6
14 - 6 = x
now solve
14 - 6 = 8
that means x equals 8 so
6 = 14 - 8
I think it would be b or c