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ohaa [14]
3 years ago
9

I need help with these two questions

Mathematics
1 answer:
BlackZzzverrR [31]3 years ago
4 0
Problem 4

Answer: 47

------------------------

Work Shown:

f(x) = x^2 - 7x + 3
f(x) = (x)^2 - 7(x) + 3
f(-4) = (-4)^2 - 7(-4) + 3 ... replace each x with -4
f(-4) = 16 - 7(-4) + 3
f(-4) = 16 + 28 + 3
f(-4) = 44 + 3
f(-4) = 47

============================================================

Problem 5

Answer: See the attached image for the table

------------------------

Work Shown:

Plug in n = 27 and we get...
C = 26 + 10*n
C = 26 + 10*27
C = 26 + 270
C = 296
The input n = 27 leads to the output C = 296. This means that 27 people will have the cost be $296

Do the same for n = 39
C = 26 + 10*n
C = 26 + 10*39
C = 26 + 390
C = 416
The input n = 39 leads to the output C = 416. This means that 39 people will have the cost be $416

and also n = 43 as well
C = 26 + 10*n
C = 26 + 10*43
C = 26 + 430
C = 456
The input n = 43 leads to the output C = 456. This means that 43 people will have the cost be $456

You might be interested in
Please help FAST:
Alex_Xolod [135]

Answer:

car a, car b

Step-by-step explanation:

car a 2x + 2= 4x

car b 3x + 3= 9x

both cars 13x

8 0
3 years ago
Arrange the geometric series from least to greatest based on the value of their sums.
son4ous [18]

Answer:

80 < 93 < 121 < 127

Step-by-step explanation:

For a geometric series,

\sum_{t=1}^{n}a(r)^{t-1}

Formula to be used,

Sum of t terms of a geometric series = \frac{a(r^t-1)}{r-1}

Here t = number of terms

a = first term

r = common ratio

1). \sum_{t=1}^{5}3(2)^{t-1}

   First term of this series 'a' = 3

   Common ratio 'r' = 2

   Number of terms 't' = 5

   Therefore, sum of 5 terms of the series = \frac{3(2^5-1)}{(2-1)}

                                                                      = 93

2). \sum_{t=1}^{7}(2)^{t-1}

   First term 'a' = 1

   Common ratio 'r' = 2

   Number of terms 't' = 7

   Sum of 7 terms of this series = \frac{1(2^7-1)}{(2-1)}

                                                    = 127

3). \sum_{t=1}^{5}(3)^{t-1}

    First term 'a' = 1

    Common ratio 'r' = 3

    Number of terms 't' = 5

   Therefore, sum of 5 terms = \frac{1(3^5-1)}{3-1}

                                                 = 121

4). \sum_{t=1}^{4}2(3)^{t-1}

    First term 'a' = 2

    Common ratio 'r' = 3

    Number of terms 't' = 4

    Therefore, sum of 4 terms of the series = \frac{2(3^4-1)}{3-1}

                                                                       = 80

    80 < 93 < 121 < 127 will be the answer.

4 0
3 years ago
Read 2 more answers
15 less than 2 times a number is represented by the algebraic expression of 2h - 15. True or false
Advocard [28]
False here are extra words tho make 20 words
8 0
3 years ago
Which of the expressions below has a 1 in the tenths place of the product? Select all that apply. A) 18.3 x 7 B) 6.5 x 4.31 C) 8
n200080 [17]

Answer: A) 18.3 x 7 and D) 5.4 x 2.8

Step-by-step explanation:

A) 18.3 x 7 = 128.10

We can infer that 1 is in the tenths place.

B) 6.5 x 4.31 = 28.015

We can infer that 1 is not in the tenths place but rather the hundredths place.

C) 8.54 x 2.3 = 19.642

We can infer that 1 is not in the tenths place.

D) 5.4 x 2.8 = 15.12

We can infer that 1 is in the tenths place.

3 0
3 years ago
A survey was conducted about the colors of shoes that people
alex41 [277]

Answer:

Option B) 0.797

Step-by-step explanation:

we know that

The probability of an event is the ratio of the size of the event space to the size of the sample space.  

The size of the sample space is the total number of possible outcomes  

The event space is the number of outcomes in the event you are interested in.  

so  

Let

x------> size of the event space

y-----> size of the sample space  

so

P=\frac{x}{y}

step 1

Find the  probability that a randomly selected person was female

In this problem we have

x=33  ----> total females

y=31+33=64  ---> total males plus total females

substitute

P=\frac{33}{64}

step 2

Find the  probability that a randomly selected person was was wearing brown shoes

In this problem we have

x=18  ----> total brown shoes

y=64  ---> total shoes

substitute

P=\frac{18}{64}

step 3

Find the  probability that a randomly selected person was either female or was wearing brown shoes

Adds the probabilities

P=\frac{33}{64}+\frac{18}{64}=\frac{51}{64}=0.797

6 0
3 years ago
Read 2 more answers
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