Let p = number of pennies.
Let n = number of nickels.
We are given that n= 2p and the total value is $8.80.
We know that a penny = $0.01 and that a nickel = $0.05.
So $0.01p + $0.05n = $8.80.
Substitute 2p for n:
$0.01p + $0.05*2p = $8.80
$0.01p + $0.10p = $8.80
$0.11p = $8.80
p = 80
So n = 2p = 2*80 = 160
Thus there are 80 pennies ($0.8) and 160 nickels ($8.00). The value of all the coins is $8.80.
A=1 and 2
B=2 and 4
C=1,2,7 and 14
D=1,2,4,and 8
Answer:
15
Step-by-step explanation:
Use the pythagorean theorem.
A² + B² = C²
In this case, A = 8, B is unknown, and C = 17. B is the side that we want to calculate.
8² + B² = 17²
64 + B² = 289
B² = 225
B = √225 = 15
not sure that that can be solved