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3 years ago

I need help with this math problem

Mathematics

1 answer:

topjm [15]3 years ago

5 0

Answer:

tui kobic tor hada kobic furi

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Which represents the solution set of 5(x+5) <85?

oksano4ka [1.4K]

Answer:

X<12 first choice.

Step-by-step explanation:

5(x+5) <85

5x +25 < 85

5x <60

X<12

Hope this helps..

8 0

3 years ago

In a sample of 60 electric motors, the average efficiency (in percent) was 85 and the standard deviation was 2. Section 05.01 Ex

jasenka [17]

Answer:

95% confidence interval for the mean efficiency is [84.483 , 85.517].

Step-by-step explanation:

We are given that in a sample of 60 electric motors, the average efficiency (in percent) was 85 and the standard deviation was 2.

So, the pivotal quantity for 95% confidence interval for the population mean efficiency is given by;

P.Q. = $\frac{\bar X - \mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\mu$ = sample average efficiency = 85

$\sigma$ = sample standard deviation = 2

n = sample of motors = 60

$\mu$ = population mean efficiency

So, 95% confidence interval for the mean efficiency, $\mu$ is ;

P(-2.0009 < $t_5_9$ < 2.0009) = 0.95

P(-2.0009 < $\frac{\bar X - \mu}{\frac{s}{\sqrt{n} } }$ < 2.0009 ) = 0.95

P( $-2.0009 \times {\frac{s}{\sqrt{n} }$ < ${\bar X - \mu}$ < $2.0009 \times {\frac{s}{\sqrt{n} }$ ) = 0.95

P( $\bar X -2.0009 \times {\frac{s}{\sqrt{n} }$ < $\mu$ < $\bar X +2.0009 \times {\frac{s}{\sqrt{n} }$ ) = 0.95

95% confidence interval for $\mu$ = [ $\bar X -2.0009 \times {\frac{s}{\sqrt{n} }$ , $\bar X +2.0009 \times {\frac{s}{\sqrt{n} }$ ]

= [ $85 -2.0009 \times {\frac{2}{\sqrt{60} }$ , $85 +2.0009 \times {\frac{2}{\sqrt{60} }$ ]

= [84.483 , 85.517]

Therefore, 95% confidence interval for the population mean efficiency is [84.483 , 85.517].

8 0

3 years ago

What number has 9 thousands and 4 less hundreds than thens

Reil [10]

..........9500..........

6 0

4 years ago

Antonio baked 150 muffins. Of all the muffins he baked, 46% of them were blueberry. How many blueberry muffins did Antonio bake?

Alenkasestr [34]

Answer:

total blueberry muffin cooked by Antonio was 69

Step-by-step explanation:

total blue berry muffins =

46/100 × 150
46/2 × 3
23 × 3
69

5 0

3 years ago

Read 2 more answers

An average orange weighs 3/5 of a pound. Based on this average, how many oranges are in six pounds of oranges? a0 oranges

8090 [49]

$\bf \begin{array}{ccll} oranges&lbs\\ \cline{1-2} 1&\frac{3}{5}\\\\ x&6 \end{array}\implies \cfrac{1}{x}=\cfrac{~~\frac{3}{5}~~}{6}\implies \cfrac{1}{x}=\cfrac{~~\frac{3}{5}~~}{\frac{6}{1}}\implies \cfrac{1}{x}=\cfrac{~~\begin{matrix} 3 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}{5}\cdot \cfrac{1}{\underset{2}{~~\begin{matrix} 6 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}} \\\\\\ \cfrac{1}{x}=\cfrac{1}{10}\implies 10=x$

8 0

3 years ago