Answer:
A = 26
Step-by-step explanation:
sum of students = classA + classB + classC
let's say classA = A, classB = B, and classC = C
A + B + C = 66
class A has five more students than class B, so A = 5 more than B so A = 5+B
class C has 2 less students than class B, so C = 2 less than class B = B -2, so C = B-2
A + B + C = 66
A = 5+B
C = B-2
substitute 5+B for A and B-2 for C in the first equation to limit this to one variable (B)
(5+B) + B + (B-2) = 66
3B + 3 = 66
subtract 3 from both sides to isolate the variable and its coefficient
3B = 63
divide both sides by 3 to solve for B
B = 21
A = 5 + B = 5 + 21 = 26
The phase shift is the value of the angle when the variable
in the angle is zero.
The angle in the sin function in this equation is (pi X + 2).
When the variable 'X' is zero, the angle is 2 .
So the phase shift of this sin function is 2 (of whatever
the unit of the angle is ... 2 degrees, 2 radians, etc.)
Make sure the question is stated clearly
Answer:
c = 6.1
Step-by-step explanation:
Given that: B = 18°
, C = 152°, and b = 4.
The missing side, c, can be determined by applying the sine rule which states that:
= 
= 
c = 
= 
= 6.0773
c = 6.1
Therefore, the value of the missing side, c, is 6.1
The answer is .4x because -3.4x+3.8x
