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3 years ago

aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa chose all that apply

Mathematics

2 answers:

lora16 [44]3 years ago

6 0

Answer:

B,C

Step-by-step explanation:

aivan3 [116]3 years ago

4 0

B and c ................

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Square? i neeed 200000000 charaters reeeeeeeee

tino4ka555 [31]

Answer:

Step-by-step explanation:

you do 6×3=18 then you do 18+7=25 last 25+17=42 then you add 2

5 0

3 years ago

What is the surface area of the box

Elena-2011 [213]

Answer:

360 in²

Step-by-step explanation:

Surface Area of the box = 2(lb+bh+hl)

= 2(12×6 + 6×6 + 6×12)

= 2(72 + 36 + 72)

= 2(180)

= 360 in²

Therefore D is the right answer.

8 0

3 years ago

8=4y-8+4 solve the equation

Yuliya22 [10]

Answer:

y=3

Step-by-step explanation:

4y-8+4=8

4y-4=8

4y-4+4=8+4

4y=12

4y/4=12/4

y=3

3 0

3 years ago

Read 2 more answers

I literally have no clue what this unit is about so help

vaieri [72.5K]

The answer is D
if the legs are 5 and 4 cm the equation to find the hypotenuse would be 5^2+4^2=c^c
5 squared is 25 and 4 squared is 16 that gives you 41, normally you would square root the 41 but it gives you a decimal number

5 0

3 years ago

Read 2 more answers

What is the solution to -x2 + 5x - 3

CaHeK987 [17]

The solution to the equation is $x=\frac{5-\sqrt{13}}{2}$ and $x=\frac{5+\sqrt{13}}{2}$

Explanation:

Given that the equation is $-x^2+5x-3=0$

We need to determine the solution of the equation.

The solution of the equation can be determined using the quadratic formula.

The quadratic formula is given by

$x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

Hence, from the equation, we have,

$a=-1,\:b=5,\:c=-3$

Substituting these values in the quadratic formula, we get,

$x=\frac{-5\pm \sqrt{5^2-4\left(-1\right)\left(-3\right)}}{2\left(-1\right)}$

Simplifying, we get,

$x=\frac{-5\pm \sqrt{25-12}}{-2}$

Simplifying the terms within the root, we get,

$x=\frac{-5\pm \sqrt{13}}{-2}$

Thus, the roots of the equation are $x=\frac{-5+ \sqrt{13}}{-2}$ and $x=\frac{-5- \sqrt{13}}{-2}$

Taking out the negative sign, we get,

$x=\frac{-(5- \sqrt{13})}{-2}$ and $x=\frac{-(5+ \sqrt{13})}{-2}$

Cancelling the negative sign, we get,

$x=\frac{5-\sqrt{13}}{2}$ and $x=\frac{5+\sqrt{13}}{2}$

Thus, the solutions of the equation are $x=\frac{5-\sqrt{13}}{2}$ and $x=\frac{5+\sqrt{13}}{2}$

7 0

4 years ago