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Eddi Din [679]
3 years ago
13

The mass of a chocolate bar is 1800g. The density of my eh chocolate is 9g/cm cubed what is its volume?

Mathematics
1 answer:
VMariaS [17]3 years ago
8 0
V=m/d
V=volume
m=mass
d=density

V=1800/9
V=200

The volume is 200 cubic centimeters
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D) 36 ounces is the answer
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Solve for A in the equation AB + CD + EFG = Z.
Semenov [28]

Answer:

A =  (Z-CD - EFG)/B

Step-by-step explanation:

AB + CD + EFG = Z.

Subtract CD and EFG from each side

AB + CD + EFG-CD -EFG = Z-CD - EFG

AB  = Z-CD - EFG

Divide each side by B

AB /B = (Z-CD - EFG)/B

A =  (Z-CD - EFG)/B

7 0
3 years ago
Consider the function f ( x ) = − 2 x 3 + 27 x 2 − 108 x + 9 . For this function there are three important open intervals: ( − [
Darya [45]

Answer:

<em>A=3 and B=6</em>

Step-by-step explanation:

<u>Increasing and Decreasing Intervals of Functions</u>

Given f(x) as a real function and f'(x) its first derivative.

If f'(a)>0 the function is increasing in x=a

If f'(a)<0 the function is decreasing in x=a

If f'(a)=0 the function has a critical point in x=a

As we can see, the critical points may define open intervals where the function has different behaviors.

We have

f ( x ) = - 2 x^3 + 27 x^2 - 108 x + 9

Computing the first derivative:

f' ( x ) = - 6 x^3 + 54 x - 108

We find the critical points equating f'(x) to zero

- 6 x^3 + 54 x - 108=0

Simplifying by -6

x^2 -9 x +18=0

We get the critical points

x=3,\ x=6

They define the following intervals

(-\infty,3),\ (3,6),\ (6,+\infty)

Thus A=3 and B=6

3 0
3 years ago
the length of a new rectangle playing field is 6 yards longer than quadruple the width. if the perimeter of the rectangle plaing
Vika [28.1K]

The length and width of a new rectangle playing field are 214 yards and 52 yards respectively.

<h3>What is the area of the rectangle?</h3>

It is defined as the area occupied by the rectangle in two-dimensional planner geometry.

The area of a rectangle can be calculated using the following formula:

Rectangle area = length x width

We have:

The length of a new rectangle playing field is 6 yards longer than quadruple the width.

Let's suppose the length is l and width is w of a rectangle:

From the problem:

l = 6 + 4w

Perimeter P = 2(l + w)

532 = 2(l + w)

Plug l = 6+4w in the above equation:

532 = 2(6 + 4w + w)

266 = 6 + 5w

260 = 5w

w = 52 yards

l = 6 +4(52) = 214 yards

Thus, the length and width of a new rectangle playing field are 214 yards and 52 yards respectively.

Learn more about the area of rectangle here:

brainly.com/question/15019502

#SPJ1

5 0
2 years ago
Surface Area of Prisms
zubka84 [21]

Answer:

6 * 24 * 10 * 10 = 14,400

Step-by-step explanation:

6 * 10 = 60.

24 * 10 = 240.

60 * 240 = 14,400.

hope this helps.

6 0
2 years ago
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