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Anni [7]
3 years ago
14

How do you find whether a pair of lines are parallel, perpendicular?

Mathematics
1 answer:
bazaltina [42]3 years ago
5 0

Answer:

If two lines are parallel they have the same slope, if they are perpendicular they have opposite slopes.

Step-by-step explanation:

Example of parallel lines: y=3x+10  &  y=3x-4

Example of perpendicular lines: y=2x-9  &  y=-1/2x+1

You might be interested in
PLEASE HELP? The standard form for the function is: P(x)=-5x^+120x-315.
dusya [7]

Answer:

P(x) = -5(x² - 12)² + 405

Step-by-step explanation:

P(x) = -5x² + 120x - 315

Factor out -5 from the first two terms

P(x) = -5(x² - 24x) - 315

Complete the square

P(x) = -5(x - 12)² - (-5(-12)²) -315

P(x) = -5(x - 12)² + 720 - 315

P(x) = -5(x - 12)² + 405

8 0
3 years ago
Andrea ran 4 3/8 miles on
MrRissso [65]
(4 3/8) + (5 1/3)

(4+5)(3/8 + 1/3)

9 + (17/24)

she ran 9 17/24 miles total
8 0
3 years ago
At a strawberry stand Luisa paid $4.50 for 2 pounds of strawberries. How much would you expect to pay for five pounds or strawbe
Daniel [21]

<u>Half</u> of 4.50 is 2.25, so for <u>one</u> pound it would be <u>$2.25</u>.

To calculate five pounds, you need to add 2.25+2.25+2.25+2.25+2.25 = <u>11.25</u>.

For <u>five</u> pounds of strawberry's, it would cost <u>$11.25</u>.

Hope this helped !

4 0
3 years ago
Read 2 more answers
(Please help) What is the rate of change of y with respect to x?
dolphi86 [110]

answer will be 2÷18=9

and the answer is 9

please mark this answer as brainlist

7 0
3 years ago
What are the possible rational roots of the polynomial equation?<br><br> 0=2x7+3x5−9x2+6
RoseWind [281]

Answer: \pm\frac{1}{1}, \pm\frac{1}{2},\pm\frac{2}{1},\pm\frac{3}{1}, \pm\frac{3}{2}

Step-by-step explanation:

We can use the Rational Root Test.

Given a polynomial in the form:

a_nx^n +a_{n- 1}x^{n - 1} + … + a_1x^1 + a_0 = 0

Where:

- The coefficients are integers.

- a_n is the leading coeffcient (a_n\neq 0)

- a_0 is the constant term a_0\neq 0

Every rational root of the polynomial is in the form:

\frac{p}{q}=\frac{\pm(factors\ of\ a_0)}{\pm(factors\ of\ a_n)}

For the case of the given polynomial:

2x^7+3x^5-9x^2+6=0

We can observe that:

- Its constant term is 6, with factors 1, 2 and 3.

- Its leading coefficient is 2, with factors 1 and 2.

 Then, by Rational Roots Test we get the possible rational roots of this polynomial:

\frac{p}{q}=\frac{\pm(1,2,3,6)}{\pm(1,2)}=\pm\frac{1}{1}, \pm\frac{1}{2},\pm\frac{2}{1},\pm\frac{3}{1}, \pm\frac{3}{2}

5 0
3 years ago
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