Domain: {-4, -2, 0, 2, 4}
range: {-2, -1, 0, 1, 2}
Answer:
Step-by-step explanation:
The anwser is C
the inverse of 5x is x/5 and the inverse of +4 is -4 so the answer would be x-4/5
Answer:
The alcohol concentration of the resulting solution is 58.4%
Step-by-step explanation:
- At first we must to find the quantity of pure alcohol in the 8 liters
∵ The alcohol concentration is 48% in 8 liters
∴ The quantity of pure alcoholic = 
liters
- She added 2 liters pure alcohol to the solution that means the solution
increased by 2 liters and alcohol quantity increased by 2 liters
∵ She added 2 liters pure alcohol
∴ The quantity of pure alcohol = 2 + 3.84 = 5.84 liters
∴ The resulting solution = 2 + 8 = 10 liters
- Now we need to find the concentration of alcohol in the resulting
solution
∵ The quantity of pure alcohol = 5.84 liters
∵ The resulting solution = 10 liters
∴ The concentrate of alcohol = 
% = 58.4%
The alcohol concentration of the resulting solution is 58.4%
We know that Sum of Angles in a Triangle is Equal to 180°
Here EBF is a Triangle
⇒ m∠EBF + m∠BEF + m∠EFB = 180°
⇒ 60° + 40° + m∠EFB = 180°
⇒ 100° + m∠EFB = 180°
⇒ m∠EFB = 180° - 100°
⇒ m∠EFB = 80°
As Line m and Line p are Parallel Lines :
Alternate Interior Angles are Equal, here Alternate Interior Angles are m∠BEF and m∠ABE
⇒ m∠BEF = m∠ABE
⇒ m∠ABE = 40°
We know that Vertically Opposite Angles are Equal, Here m∠GFI and m∠EFB are Vertically Opposite Angles.
⇒ m∠GFI = m∠EFB
⇒ m∠GFI = 80°
We can notice that m∠DEB and m∠BEF form a Linear Pair
⇒ m∠DEB + m∠BEF = 180°
⇒ m∠DEB + 40° = 180°
⇒ m∠DEB = 180° - 40°
⇒ m∠DEB = 140°
We can notice that Sum of Angles m∠CBF and m∠EBF and m∠ABE is 180°
⇒ m∠CBF + m∠EBF + m∠ABE = 180°
⇒ m∠CBF + 60° + 40° = 180°
⇒ m∠CBF + 100° = 180°
⇒ m∠CBF = 180° - 100°
⇒ m∠CBF = 80°
We can notice that m∠BFG and m∠EFB form a Linear Pair
⇒ m∠BFG + m∠EFB = 180°
⇒ m∠BFG + 80° = 180°
⇒ m∠BFG = 180° - 80°
⇒ m∠BFG = 100°
We know that Vertically Opposite Angles are Equal, Here m∠BFG and m∠IFE are Vertically Opposite Angles.
⇒ m∠BFG = m∠IFE
⇒ m∠IFE = 100°
Answer:
look at the photo I have sent
