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2 years ago

1

Mathematics

1 answer:

77julia77 [94]2 years ago

4 0

I believe the answer should b the second option :)

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Solve this and get 20 points

VikaD [51]

take x =initial deposit amount. then make equation:

x+75.5+55.25-25.15-18.65 = 210.85

simplify:

x+86.95 = 210.85

x=210.85 - 86.95

x=123.90

so Initial deposit amount is $123.90

check: 210.85+18.65+25.15-55.25-75.5 = 123.9

123.9 = 123.9

4 0

2 years ago

Which is a needed step to prove that AABF = AEDG?

Gwar [14]

Answer: helllloooooooooooooo000000oooo

Step-by-step explanation:

7 0

2 years ago

The area of a square is 100. The length of its diagonal is approximately:

mr_godi [17]

Answer:

10 $\sqrt{2\\} \\$ or 14.14 appromiximately

Step-by-step explanation:

Area of square = 100

So length on side = 10 because all sides of square equal.

Length of Diagonal = Side x $\sqrt{2}$

So the length of diagonal is 14.14 approximately

6 0

2 years ago

Find the quotient of '(16t^2-4)/(8t+4)'

Marizza181 [45]

here we have to find the quotient of '(16t^2-4)/(8t+4)'

now we can write 16t^2 - 4 as (4t)^2 - (2)^2

the above expression is equal to (4t + 2)(4t - 2)

there is another expression (8t + 4)

the expression can also be written as 2(4t + 2)

now we have to divide both the expressions

by dividing both the expressions we would get (4t + 2)(4t - 2)/2(4t + 2)

therefore the quotient is (4t - 2)/2

the expression comes out to be (2t - 1)

3 0

2 years ago

A right cylinder has a radius of 6 m and a surface area of 84 m². Find the surface area of a similar cylinder with a radius of 2

dlinn [17]

Answer:

The surface area of the second cylinder is equal to $9.33\ m^{2}$

Step-by-step explanation:

we know that

If two figures are similar then

the ratio of their surfaces areas is equal to the scale factor squared

Let

z-------> the scale factor

x------> the surface area of the smaller cylinder (second cylinder)

y-------> the surface area of the original cylinder (first cylinder)

$z^{2}=\frac{x}{y}$

Step 1

Find the scale factor

$z=\frac{2}{6}=\frac{1}{3}$

Step 2

Find the surface area of the second cylinder

we have

$z=\frac{1}{3}$

$y=84\ m^{2}$

substitute and solve for x

$(\frac{1}{3})^{2}=\frac{x}{84}$

$x=\frac{1}{9}*84=9.33\ m^{2}$

5 0

2 years ago