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cupoosta [38]
2 years ago
12

Please help!!!!!!!!!!!

Mathematics
2 answers:
Margaret [11]2 years ago
8 0
I agree with the answer above
liq [111]2 years ago
5 0
It should be this y=1/2x+3
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Solve for x <br> 1. 6<br> 2. 4<br> 3. -5<br> 4.-10
kramer
The answer I think is 6
6 0
2 years ago
How can i get answer 5 for -10 - (+5) ?​
timama [110]

Answer:

- 10 - (-20 + 5)

Step-by-step explanation:

- 10 - (-20 + 5)

- 10 - (-15) = -10 + 15

-10 + 15 = 5

have a nice day and mark me brainliest! :)

4 0
3 years ago
Compute the loss of head and pressure drop in 200 ft of horizontal 6-in diameter asphalted cast iron pipe carrying water with a
laiz [17]

Answer:

The answer is below

Step-by-step explanation:

12 inches = 1 ft.

6 inches = 6 inches * (1 ft./12 inches) = 0.5 ft.

Therefore the diameter of the cast iron (D) = 6 inches = 0.5 ft.

The area of cast iron (A) = πD²/4 = π(0.5)²/4 = 0.196 ft²

The velocity (V) = 6 ft./s, the acceleration due to gravity (g) = 32.2 ft./s²

ε/D = 0.0004 ft./ 0.5 ft. = 0.0008

Using the moody chart, find the line ε/D = 0.0008 and determine the point of intersection with the vertical line R = 2.7 * 10⁵. Hence we get f = 0.02.

The head loss (h) is:

h_f=f*\frac{L}{d}* \frac{V^2}{2g}=0.02*\frac{200\ ft}{0.5\ ft} *\frac{(6\ ft/s)^2}{2*32.2\ ft/s^2}=4.5\ ft

The pressure drop (Δp) is:

Δp = ρgh_f = (62.4\ lbf/ft^3)(4.5\ ft)= 280\ lbf/ft^2

5 0
3 years ago
Can you help me find t value in this problem?
Eduardwww [97]

we have a maximum at t = 0, where the maximum is y = 30.

We have a minimum at t = -1 and t = 1, where the minimum is y = 20.

<h3>How to find the maximums and minimums?</h3>

These are given by the zeros of the first derivation.

In this case, the function is:

w(t) = 10t^4 - 20t^2 + 30.

The first derivation is:

w'(t) = 4*10t^3 - 2*20t

w'(t) = 40t^3 - 40t

The zeros are:

0 = 40t^3 - 40t

We can rewrite this as:

0 = t*(40t^2 - 40)

So one zero is at t = 0, the other two are given by:

0 = 40t^2 - 40

40/40 = t^2

±√1 = ±1 = t

So we have 3 roots:

t = -1, 0, 1

We can just evaluate the function in these 3 values to see which ones are maximums and minimums.

w(-1) = 10*(-1)^4 - 20*(-1)^2 + 30 = 10 - 20 + 30 = 20

w(0) = 10*0^4 - 20*0^2 + 30    = 30

w(1) =  10*(1)^4 - 20*(1)^2 + 30 =  20

So we have a maximum at x = 0, where the maximum is y = 30.

We have a minimum at x = -1 and x = 1, where the minimum is y = 20.

If you want to learn more about maximization, you can read:

brainly.com/question/19819849

6 0
2 years ago
Identify the mapping diagram that represents the relation and determine whether the relation is a function. {(–8, –6), (–5, 2),
SashulF [63]
Do you have the answer options? Sorry, can't answer without them ):
8 0
3 years ago
Read 2 more answers
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