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HACTEHA [7]
3 years ago
15

the sum of present ages ofa father and his son is 60years .if both of them live until the son becomes as old as the father is no

w the sum of their ages will be 120 years then find the present ages?
Mathematics
1 answer:
Nikitich [7]3 years ago
3 0

I might be wrong but you tell me,

The father is 60 years old.

Son lives to be 60.

Total is 120.

Both die at the age of 60.

Could the son have been a newborn?

Idk. I don't understand it.

Wait,  sum of present ages is 60. The son has to be younger by at least 20. Double it again. No, even then newborn is 0 and then 60= 60. Son lives toll he's 60 and dies, 120. Sorry, I tried. What are your possible choices?


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Albert is five years younger than his brother bill. Write an equation that shows Albert's age with respect to Bills.
Charra [1.4K]

Answer:

A=B-5

Step-by-step explanation:

Albert is known as the variable A.

Bill is known as the variable B.

If Albert is 5 years younger than Bill. Then the equation will be

a=b-5

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3 years ago
The length of a rectangle is twice the width. Given that the perimeter of the rectangle is 24 feet, how many square feet are in
just olya [345]

Answer:

Area = 32feet²

Step-by-step explanation:

Perimeter of a rectangule = 2(length+width)

Then:

g = 2w               Eq. 1

2(g+w) = 24       Eq. 2

g = length

w = width

From Eq. 2:

(2*g + 2*w) = 24

2g + 2w = 24      

2w = 24 - 2g            Eq. 3

Matching Eq. 1  and Eq. 3

g = 24 - 2g

g + 2g = 24

3g = 24

g = 24/3

g = 8 feet

From Eq. 1

g = 2w

8 = 2w

8/2 = w

w = 4 feet

Check:

From Eq. 2

2(g+w) = 24

2(8+4) = 24

2*12 = 24

Answer:

Area of a rexctangle = length * width

Then:

Area = 8feet * 4feet

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5 0
1 year ago
Students who have completed a speed reading course have reading speeds that are normally distributed with a mean of 950 words pe
VikaD [51]

Answer:

36.04% probability that at most two of them would read at less than 850 words per minute

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the binomial probability distribution.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

Percentage of students who read less than 850 words per minute.

Pvalue of Z when X = 850. The mean is \mu = 950 and the standard deviation is \sigma = 200

Z = \frac{X - \mu}{\sigma}

Z = \frac{850 - 950}{200}

Z = -0.5

Z = -0.5 has a pvalue of 0.3085.

30.85 of students read less than 850 words per minute.

If 10 students are selected at random, what is the probability that at most two of them would read at less than 850 words per minute

This is P(X \leq 2) when n = 10, p = 0.3085. So

P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{10,0}.(0.3085)^{0}.(0.6915)^{10} = 0.0250

P(X = 1) = C_{10,1}.(0.3085)^{1}.(0.6915)^{9} = 0.1115

P(X = 2) = C_{10,2}.(0.3085)^{2}.(0.6915)^{8} = 0.2239

P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2) = 0.0250 + 0.1115 + 0.2239 = 0.3604

36.04% probability that at most two of them would read at less than 850 words per minute

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It's not possible to know, because you're not letting us see
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