W*l=A
w=8
l=3x
8*3x= A
That would be the equation
Answer:
c
Step-by-step explanation:
The sound wave with a <u>frequency of 20</u> waves/sec is 800 longer than the wavelength of a sound wave with a <u>frequency of 16,000</u> waves/sec
<h3>Calculating wavelength </h3>
From the question, we are to determine how many times longer is the first sound wave compared to the second sound water
Using the formula,
v = fλ
∴ λ = v/f
Where v is the velocity
f is the frequency
and λ is the wavelength
For the first wave
f = 20 waves/sec
Then,
λ₁ = v/20
For the second wave
f = 16,000 waves/sec
λ₂ = v/16000
Then,
The factor by which the first sound wave is longer than the second sound wave is
λ₁/ λ₂ = (v/20) ÷( v/16000)
= (v/20) × 16000/v)
= 16000/20
= 800
Hence, the sound wave with a <u>frequency of 20</u> waves/sec is 800 longer than the wavelength of a sound wave with a <u>frequency of 16,000</u> waves/sec
Learn more on Calculating wavelength here: brainly.com/question/16396485
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Answer: 
Step-by-step explanation:
For this exercise it is important to know the definition of "Dilation".
A Dilation is defined as a transformation in which the Image (The figure obtained after the transformation) and the Pre-Image (The original figure before the transformation) have the same shape but have different sizes.
If the Dilation is centered at the origin, and knowing the scale factor of 
, you need to multiply each coordinate of the point T by the scale factor in order to find the coordinates of the Image T'.
Knowing that the point T has the following coordinates:
You get that the coordinates of the Image T' are the shown below:
7 × (-3) ×(-2)2 =
7 × -3 × -4 = (you have to eliminate all parenthesis in the equation.)
7 × -12 = -84
so your answer would be: C
