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dimulka [17.4K]
3 years ago
13

GameStop was selling Ps5’s. They sold 100. They sold each ps5 for 500. But they got ps5’s on discount $30 off from each GameStop

. So they bought the Ps5s for $470 but they sold them to the customers for more. How much did they collect/make? How much were their expenses? How much was their profit?
Mathematics
1 answer:
Cerrena [4.2K]3 years ago
3 0
They made 3000$ in profit 500x100=50k

470x100=47k
47,000-50000=3000
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The volume of a rectangular prism is 16.328 cm³. The height is 3.14 cm.
Ghella [55]

Answer:

The area of the base is = 5.2 cm²

Step-by-step explanation:

<em>First, we need to know the formula to calculate volume:</em>

volume=height XBase area

<em>if we change to our equations to the values we know:</em>

16.328 = 3.14XB

<em>Since 3.14 is multiplying B,we can pass it to divide the volume to the left side:</em>

\frac{16.328}{3.14} =B

<em>We calculate the operation=</em>

\frac{16.328}{3.14} =5.2

<em>And the answer is 5.2 cm²</em>

<em>Let me know if you have any question :D</em>

5 0
3 years ago
Use the information provided to determine a 95% confidence interval for the population variance. A researcher was interested in
Leno4ka [110]

Answer:

The 95% confidence interval for the population variance is (8.80, 32.45).

Step-by-step explanation:

The (1 - <em>α</em>)% confidence interval for the population variance is given as follows:

\frac{(n-1)\cdot s^{2}}{\chi^{2}_{\alpha/2}}\leq \sigma^{2}\leq \frac{(n-1)\cdot s^{2}}{\chi^{2}_{1-\alpha/2}}

It is provided that:

<em>n</em> = 20

<em>s</em> = 3.9

Confidence level = 95%

⇒ <em>α</em> = 0.05

Compute the critical values of Chi-square:

\chi^{2}_{\alpha/2, (n-1)}=\chi^{2}_{0.05/2, (20-1)}=\chi^{2}_{0.025,19}=32.852\\\\\chi^{2}_{1-\alpha/2, (n-1)}=\chi^{2}_{1-0.05/2, (20-1)}=\chi^{2}_{0.975,19}=8.907

*Use a Chi-square table.

Compute the 95% confidence interval for the population variance as follows:

\frac{(n-1)\cdot s^{2}}{\chi^{2}_{\alpha/2}}\leq \sigma^{2}\leq \frac{(n-1)\cdot s^{2}}{\chi^{2}_{1-\alpha/2}}

\frac{(20-1)\cdot (3.9)^{2}}{32.852}\leq \sigma^{2}\leq \frac{(20-1)\cdot (3.9)^{2}}{8.907}\\\\8.7967\leq \sigma^{2}\leq 32.4453\\\\8.80\leq \sigma^{2}\leq 32.45

Thus, the 95% confidence interval for the population variance is (8.80, 32.45).

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