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soldi70 [24.7K]
3 years ago
11

Angles 1 and 2 are supplementary

Mathematics
2 answers:
Dvinal [7]3 years ago
7 0

Answer:

Read below

Step-by-step explanation:

I don't understand the answer choices, but supplementary angles add up to 180°. It looks like the third option is correct.

7nadin3 [17]3 years ago
4 0

Answer:

<1 + <2 = 180 degrees

Step-by-step explanation:

Supplementary angles add to 180 degrees

<1 + <2 = 180 degrees

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Which expression is equivalent to 4(x^3)(2x)^-4
AVprozaik [17]

Answer:

=\frac{4x^{3}}{16 x^{4}}

Step-by-step explanation:

4(x^{3} )(2x)^{-4}

=\frac{4x^{3}}{(2x)^{4}}

=\frac{4x^{3}}{2^{4} x^{4}}

=\frac{4x^{3}}{16 x^{4}}

3 0
3 years ago
A rectangle has width that is 6 meters less than the length. The area of the rectangle is 280 square meters. Find the dimensions
salantis [7]

Dimensions are length 20 meter and width 14 meter

<em><u>Solution:</u></em>

Let "a" be the length of rectangle

Let "b" be the width of rectangle

Given that,

<em><u>A rectangle has width that is 6 meters less than the length</u></em>

Width = length - 6

b = a - 6

The area of the rectangle is 280 square meters

<em><u>The area of the rectangle is given by formula:</u></em>

Area = length \times width

<em><u>Substituting the values we get,</u></em>

Area = a \times (a-6)\\\\280 = a^2-6a\\\\a^2-6a -280=0

<em><u>Solve the above equation by quadratic formula</u></em>

\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}\\\\\quad x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

\mathrm{For\:}\quad a=1,\:b=-6,\:c=-280:\quad a_{1,\:2}=\frac{-\left(-6\right)\pm \sqrt{\left(-6\right)^2-4\cdot \:1\left(-280\right)}}{2\cdot \:1}

a =\frac{6 \pm \sqrt{36+1120}}{2}\\\\a = \frac{6 \pm \sqrt{1156}}{2}\\\\a = \frac{6 \pm 34}{2}\\\\Thus\ we\ have\ two\ solutions\\\\a = \frac{6+34}{2} \text{ or } a = \frac{6-34}{2}\\\\a = 20 \text{ or } a = -14

Since, length cannot be negative, ignore a = -14

<em><u>Thus solution of length is a = 20</u></em>

Therefore,

width = length - 6

width = 20 - 6 = 14

Thus dimensions are length 20 meter and width 14 meter

6 0
3 years ago
(9x + 1) -(-7x2 + 4x + 10)
alexandr1967 [171]
On your papers does it say what x equals?
8 0
3 years ago
Read 2 more answers
What is the solution for this system of linear equations?<br> {23x+4=y<br> 4−2x=y
liubo4ka [24]
We can subsitute since
23x+4=y and
4-2x=y
therefor
23x+4=y=4-2x
so
23x+4=4-2x
minus 4 on both sides
23x=-2x
add 2x to both sides
25x=0
divide both sides by... uh oh
I guess x=0

sub
4-2(0)=y
4-0=y
4=y

the solution is (0,4)
3 0
3 years ago
1. Find a vector in R^3 which is not in the span of the set S-((1,2, -2), (2, -1, 1). Explain.
pav-90 [236]

Answer:

Step-by-step explanation:

A vector in R^3 which is not in the span of the set S {(1,2,-2) and (2,-1,1)

If a vector is in the span it can be represented as a linear combination of these two vectors

Let S1 = (1,2,-2) and S2 = (2,-1,1)

i.e. any vector which is of the form

\alpha S1+\beta S2\\=(\alpha +2\beta,2\alpha -\beta,-2\alpha +\beta)

Where alpha and beta are any real numbers

Any vector not in this form will not be in the span

i.e. say if alpha = beta =1,

then spanned vector = (3,1,-1)

If we change one coordinate alone say

(3,0,-1) this cannot be represented as a linear combination hence this would be the answer.

8 0
3 years ago
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