-4p+1 = -4(2)+1 = -8+1 = -7
Answer:
The first digit of a two digit number can be any of digits 1 - 9. It cannot be 0 though. Therefore there are 9 possible digits for the first place.
There are 5 possible digits for the second position. The two digit number has to be odd and therefore the final digit must be 1,3,5,7 or 9
Therefore for each and every one of the nine first digits there are 5 digits that the second can be.
Therefore ANSWER = 9 * 5 = 45 possible permutations.
2. The largest two digit number = 99
Subtract 57 and you get 42
ANSWER = 42
The forty two numbers are 58 ,59, 60, 61......98, 99
<span>10 units to the right and 2 units up,</span>
Step-by-step explanation:
Answer:
c. x=50; m< LOK = 114
Step-by-step explanation:
(x+64) + 66 = 180
x + 130 = 180
x = 50
