All categories

3 years ago

There are 14 girls and 12 boys in a class. What is the ratio of girls to students? Simplify your answer

Mathematics

1 answer:

ivann1987 [24]3 years ago

7 0

Answer:14:12

Step-by-step explanation:

You might be interested in

What is the slope of the line through the points (1,5) and (-2,-4)?

olasank [31]

Answer:

slope = 3

Step-by-step explanation:

Use the coordinates of the points to determine the slope.

3 0

3 years ago

Need help !Which picture shows the correct graph of |x| = 3?

lana66690 [7]

Answer:

F. Picture F

Step-by-step explanation:

4 0

3 years ago

Evaluate -x - y when x = -12 and y = 2

xz_007 [3.2K]

Answer:

-14

Step-by-step explanation:

subtract

8 0

3 years ago

Read 2 more answers

Answer:

emmainna [20.7K]

Let the numbers be n, n+2, n+4

Sum equals too= 13+2(n+4), which is 2n+21

a) Equation--> n+n+2+n+4= 2n+21

b) Solution--> 3n+6= 2n+21

=> n= 15

c) Second number--> 17 (15+2)

Third number--> 19 (15+4)

d) 15+15+2+15+4=30+21

=> 51= 51

So, the equation is true.

And pls mark me brainliesttt :)))

8 0

2 years ago

What is the perimeter of this quadrilateral?<br> (5,5)<br> (2, 4)<br> (4, 1)<br> (6, 1)

lbvjy [14]

$~\hfill \stackrel{\textit{\large distance between 2 points}}{d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}}~\hfill~ \\\\[-0.35em] ~\dotfill\\\\ A(\stackrel{x_1}{5}~,~\stackrel{y_1}{5})\qquad B(\stackrel{x_2}{2}~,~\stackrel{y_2}{4}) ~\hfill AB=\sqrt{[ 2- 5]^2 + [ 4- 5]^2} \\\\\\ AB=\sqrt{(-3)^2+(-1)^2}\implies \boxed{AB=\sqrt{10}} \\\\[-0.35em] ~\dotfill\\\\ B(\stackrel{x_1}{2}~,~\stackrel{y_1}{4})\qquad C(\stackrel{x_2}{4}~,~\stackrel{y_2}{1}) ~\hfill BC=\sqrt{[ 4- 2]^2 + [ 1- 4]^2}$

$BC=\sqrt{2^2+(-3)^2}\implies \boxed{BC=\sqrt{13}} \\\\[-0.35em] ~\dotfill\\\\ C(\stackrel{x_1}{4}~,~\stackrel{y_1}{1})\qquad D(\stackrel{x_2}{6}~,~\stackrel{y_2}{1}) ~\hfill CD=\sqrt{[ 6- 4]^2 + [ 1- 1]^2} \\\\\\ CD=\sqrt{2^2+0^2}\implies \boxed{CD=2} \\\\[-0.35em] ~\dotfill\\\\ D(\stackrel{x_1}{6}~,~\stackrel{y_1}{1})\qquad A(\stackrel{x_2}{5}~,~\stackrel{y_2}{5}) ~\hfill DA=\sqrt{[ 5- 6]^2 + [ 5- 1]^2}$

$DA=\sqrt{(-1)^2+4^2}\implies \boxed{DA=\sqrt{17}} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{\Large Perimeter}}{\sqrt{10}~~ + ~~\sqrt{13}~~ + ~~2~~ + ~~\sqrt{17}}~~ \approx ~~ 12.89$

8 0

2 years ago