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Pachacha [2.7K]
3 years ago
5

Simplify the expression using positive exponents. 3^8/3^4

Mathematics
2 answers:
dangina [55]3 years ago
5 0
I don’t know what it is tbh
Ksju [112]3 years ago
4 0
Check this out mate! GOOD LUCK

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Orthogonalizing vectors. Suppose that a and b are any n-vectors. Show that we can always find a scalar γ so that (a − γb) ⊥ b, a
jeka57 [31]

Answer:

\\ \gamma= \frac{a\cdot b}{b\cdot b}

Step-by-step explanation:

The question to be solved is the following :

Suppose that a and b are any n-vectors. Show that we can always find a scalar γ so that (a − γb) ⊥ b, and that γ is unique if b \neq 0. Recall that given two vectors a,b  a⊥ b if and only if a\cdot b =0 where \cdot is the dot product defined in \mathbb{R}^n. Suposse that b\neq 0. We want to find γ such that (a-\gamma b)\cdot b=0. Given that the dot product can be distributed and that it is linear, the following equation is obtained

(a-\gamma b)\cdot b = 0 = a\cdot b - (\gamma b)\cdot b= a\cdot b - \gamma b\cdot b

Recall that a\cdot b, b\cdot b are both real numbers, so by solving the value of γ, we get that

\gamma= \frac{a\cdot b}{b\cdot b}

By construction, this γ is unique if b\neq 0, since if there was a \gamma_2 such that (a-\gamma_2b)\cdot b = 0, then

\gamma_2 = \frac{a\cdot b}{b\cdot b}= \gamma

6 0
3 years ago
Help me please!!!! Please
Monica [59]

Answer:

5

Step-by-step explanation:

it's not necessary to round to the nearest tenth just simply half 10

3 0
2 years ago
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