Answer:
6(3+2)
Step-by-step explanation:
Distributive property:
ab + ac = a(b+c)
where a = greatest common factor (GCF)
GCF of each factor
18 = 2×3×3
12 = 2×2×3
GCF of 18 and 12 = 2×3
= 6
Therefore,
18 + 12 = 6(3) + 6(2)
= 6(3+2)
Where,
6 = a
3 = b
2 = c
ab + ac = a(b+c)
Answer:
(ab - 6)(2ab + 5)
Step-by-step explanation:
Assuming you require the expression factorised.
2a²b² - 7ab - 30
Consider the factors of the product of the coefficient of the a²b² term and the constant term which sum to give the coefficient of the ab- term
product = 2 × - 30 = - 60 and sum = - 7
The factors are - 12 and + 5
Use these factors to split the ab- term
= 2a²b² - 12ab + 5ab - 30 ( factor the first/second and third/fourth terms )
= 2ab(ab - 6) + 5(ab - 6) ← factor out (ab - 6) from each term
= (ab - 6)(2ab + 5) ← in factored form
Answer:
560
Step-by-step explanation:
10 x 9 = 90 x 6 = 560
x² - 4x - 12 = 0
Factor the left side: (x + 2) · (x - 6) = 0
The equation is true if either factor is zero.
If (x + 2) = 0 then x = -2 .
If (x - 6) = 0 then x = 6 .
(2,2)
(x1+x2)/2, (y1-y2)/2
(-2+6)/2=(2)
(-2+6)/2=2
