I need help with all the questions plzzz show work and I’ll give u brainliest plzzzzzZzZzZz i need help plzZZz
1 answer:
Answer:
The answers are given below.
Step-by-step explanation:
7. EFGH is a rectangle. Slope of HE is
So, the slope of EF is
=
8 .PQRS is a square.
So, m∠QSR = 45°
[since the diagonals bisect the internal angles of a square]
9. m∠PTQ = 90°
[since the diagonals of a square intersect each other at right angles]
10. RT = 24 unit ,
so,
PR = unit
= 48 unit [since the diagonals of a square bisect each other]
So, SQ = PR = 48 unit
[since the diagonals of a square are equal]
11. Yes, a squae is a rectangle
12. Since RSTU is a rectangle,
so, ∠RUS + ∠SUT = 90°
⇒3x + 6 + 5x - 4 = 90°
⇒x = 11°
So, ∠RUS = 3x + 6 = 39°
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Answer:
(a) The histogram is shown below.
(b) E (X) = 4.2
(c) SD (X) = 2.73
Step-by-step explanation:
Let <em>X</em> = <em>r</em><em> </em>= a driver will tailgate the car in front of him before passing.
The probability that a driver will tailgate the car in front of him before passing is, P (X) = <em>p</em> = 0.35.
The sample selected is of size <em>n</em> = 12.
The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> = 12 and <em>p</em> = 0.35.
The probability function of a binomial random variable is:
(a)
For <em>X</em> = 0 the probability is:
For <em>X</em> = 1 the probability is:
For <em>X</em> = 2 the probability is:
Similarly the remaining probabilities will be computed.
The probability distribution table is shown below.
The histogram is also shown below.
(b)
The expected value of a Binomial distribution is:
The expected number of vehicles out of 12 that will tailgate is:
Thus, the expected number of vehicles out of 12 that will tailgate is 4.2.
(c)
The standard deviation of a Binomial distribution is:
The standard deviation of vehicles out of 12 that will tailgate is:
Thus, the standard deviation of vehicles out of 12 that will tailgate is 2.73.
