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3 years ago

Arrange the following polynomial into descending order and identify the 3rd term.

2 answers:

6 0

Thank you for posting your question here at brainly. Feel free to ask more questions.

The best and most correct answer among the choices provided by the question is 18x.

Hope my answer would be a great help for you.

mart [117]3 years ago

6 0

Answer with Step-by-step explanation:

We are given a polynomial:

$18x + 2x^3 - 3x^2 + 10$

We have to arrange it in descending order and then identify its third term

Polynomial in descending order is:

$2x^3-3x^2+18x+10$

As we can clearly see the third term is:

18x

Hence,

Polynomial in descending order is:

$2x^3-3x^2+18x+10$

and the third term is:

18x

You might be interested in

Determine the greatest common factor of 28xy^9z and 32x^2y^7z

RSB [31]

Answer:

GCF = 4xy⁷z

Step-by-step explanation:

Do Prime Factorizations for each term and select only those terms common to each:

28xy⁹z = 2·2·7·x·y·y·y·y·y·y·y·y·y·z

32x²y⁷z = 2·2·2·2·2·x·x·y·y·y·y·y·y·y·z

GCF = 2·2·x·y·y·y·y·y·y·y·z

GCF = 4xy⁷z

5 0

2 years ago

Explain a thought process you might use when trying to find the additive or multiplicative inverse of a number or expression. ..

gizmo_the_mogwai [7]

Definition of additive inverse.- If two numbers are added together and the sum is zero, they are the additive inverse of each other.

......................................... IF A + B = 0 , they are the additive inverse of each other.


Multiplicative Inverse.- If two numbers are multiplied together and the product is one. They are the multiplicative inverse of each other, also called reciprocal. 

......................................... A.B = 1 , they are the multiplicative inverse of each other.


Example of: 

Additive inverses :................ 5 + ( - 5 ) = 0 

Multiplicative inverses...........5 x 1/5 = 1

3 0

3 years ago

4x-5+3m-2x ; x=5 and m=7

Viefleur [7K]

Answer:

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Help!! Solving absolute value inequalities

goblinko [34]

Answer:

48. $x \geq -7$ or $x \leq 31$

51. $x \leq 13$ or $x \geq 3$

54. $x < \frac{5}{2}$ or $x > \frac{-15}{2}$

57. $x < \frac{18}{7}$ or $x > -4$

Step-by-step explanation:

48. $| 12 - x | \leq 19$

-There are two equations:

Equation 1:

$12 - x \leq 19$

Equation 2:

$12 - x \geq -19$

Solving equation 1:

$12 - x \leq 19$

$12- 12 - x \leq 19 - 12$

$-x \leq 7$

$\frac{-x}{-1} \leq \frac{7}{-1}$

$x \geq -7$ (Inequality sign changed, because of dividing by a negative number)

-Solving equation 2:

$12 - x \geq -19$

$12 - 12 - x \geq -19 - 12$

$-x \geq -31$

$\frac{-x}{-1} \geq \frac{-31}{-1}$

$x \leq 31$ (Inequality sign changed, because of dividing by a negative number)

-Answers:

$x \geq -7$ or $x \leq 31$

51. $| x - 8 | \leq 5$

-There are two equations:

Equation 1:

$x - 8 \leq 5$

Equation 2:

$x - 8 \geq - 5$

-Solving equation 1:

$x - 8 \leq 5$

$x - 8 + 8 \leq 5 + 8$

$x \leq 13$

-Solving equation 2:

$x - 8 \geq - 5$

$x - 8 + 8 \geq - 5 + 8$

$x \geq 3$

Answers:

$x \leq 13$ or $x \geq 3$

54. $| 4x + 10 | < 20$

-There are two equations:

Equation 1:

$4x + 10 < 20$

Equation 2:

$4x + 10 > -20$

-Solving equation 1:

$4x + 10 < 20$

$4x + 10 - 10 < 20 - 10$

$4x < 10$

$\frac{4x}{4} < \frac{10}{4}$

$x < \frac{5}{2}$

-Solving equation 2:

$4x + 10 > -20$

$4x + 10 - 10 > -20 - 10$

$4x > -30$

$\frac{4x}{4} > \frac{-30}{4}$

$x > \frac{-15}{2}$

-Answers:

$x < \frac{5}{2}$ or $x > \frac{-15}{2}$

57. $| 7x + 5 | < 23$

-There are two equations:

Equation 1:

$7x + 5 < 23$

Equation 2:

$7x + 5 > -23$

-Solving equation 1:

$7x + 5 < 23$

$7x + 5 - 5 < 23 - 5$

$7x < 18$

$\frac{7x}{7} < \frac{18}{7}$

$x < \frac{18}{7}$

Solving equation 2:

$7x + 5 > -23$

$7x + 5 - 5 > -23 - 5$

$7x > -28$

$\frac{7x}{7} > \frac{-28}{7}$

$x > -4$

Answers:

$x < \frac{18}{7}$ or $x > -4$

And we are finished.

5 0

3 years ago

Solve the radical equation. Be sure to check all solutions to eliminate extraneous solutions.

Liono4ka [1.6K]

The solution of the radical equation is x = 5 / 3.

<h3>How to solve radical equation?</h3>

The radical equation can be solved by isolating x.

Therefore, the radical equation can be solved as follows:

√3x - 1 - 2 = 0

add 2 to both sides

√3x - 1 - 2 = 0

√3x - 1 - 2 + 2 = 0 + 2

√3x - 1 = 2

square both sides

√3x - 1 = 2

(√3x - 1 )² = 2²

Hence,

(√3x - 1 )² = 2²

3x - 1 = 4

Therefore, add 1 to both sides

3x - 1 = 4

3x - 1 + 1 = 4 + 1

3x = 5

divide both sides by 3

3x = 5

3x / 3 = 5 / 3

x = 5 / 3

Therefore, the solution of the radical equation is x = 5 / 3.

learn more on radical equation here: brainly.com/question/28442352

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7 0

1 year ago