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AveGali [126]
4 years ago
8

Arrange the following polynomial into descending order and identify the 3rd term.

Mathematics
2 answers:
Vera_Pavlovna [14]4 years ago
6 0
Thank you for posting your question here at brainly. Feel free to ask more questions.  

The best and most correct answer among the choices provided by the question is <span>18x</span>.<span>       
    </span><span>
Hope my answer would be a great help for you.</span>
mart [117]4 years ago
6 0

Answer with Step-by-step explanation:

We are given a polynomial:

18x + 2x^3 - 3x^2 + 10

We have to arrange it in descending order and then identify its third term

Polynomial in descending order is:

2x^3-3x^2+18x+10

As we can clearly see the third term is:

18x

Hence,

Polynomial in descending order is:

2x^3-3x^2+18x+10

and the third term is:

18x

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Describe fully the single transformation that maps triangle a onto triangle b
Airida [17]

Answer:

Reflection about y=2

Step-by-step explanation:

Triangle A should be reflected about y=2 to map it onto Triangle B.

8 0
3 years ago
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Sorry for the bad quality.
ser-zykov [4K]

Answer:

B and C

Step-by-step explanation:

8 0
3 years ago
PLS HELP MEEE !!!!!
kotykmax [81]

Answer:

5 terms

Step-by-step explanation:

x is one term

-3 is one term

2y is one term

-16 is one term

4x is one term

5 terms in total

7 0
3 years ago
Read 2 more answers
<img src="https://tex.z-dn.net/?f=8x%20%2B%204%20%3D%205x%20-%2011%20" id="TexFormula1" title="8x + 4 = 5x - 11 " alt="8x + 4 =
Anon25 [30]
8x + 4 = 5x - 11

Subtract 5x from both sides:
3x + 4 = -11

Subtract 4 from both sides:
3x = -15

Divide both sides by 3:
x = -5

Answer : x = -5
7 0
4 years ago
What are the fourth roots of 6+6√(3i) ?
Helen [10]

Answer:

Step-by-step explanation:

The genral form of a complex number in rectangular plane is expressed as z = x+iy

In polar coordinate, z =rcos ∅+irsin∅ where;

r is the modulus = √x²+y²

∅ is teh argument = arctan y/x

Given thr complex number z = 6+6√(3)i

r = √6²+(6√3)²

r = √36+108

r = √144

r = 12

∅ = arctan 6√3/6

∅ = arctan √3

∅ = 60°

In polar form, z = 12(cos60°+isin60°)

z = 12(cosπ/3+isinπ/3)

To get the fourth root of the equation, we will use the de moivres theorem; zⁿ = rⁿ(cosn∅+isinn∅)

z^1/4  = 12^1/4(cosπ/12+isinπ/12)

When n = 1;

z1 =  12^1/4(cosπ/3+isinn/3)

z1 = 12^1/4cis(π/3)

when n = 2;

z2 = 12^1/4(cos2π/3+isin2π/3)

z2 = 12^1/4cis(2π/3)

when n = 3;

z2 = 12^1/4(cosπ+isinπ)

z2 = 12^1/4cis(π)

when n = 4;

z2 = 12^1/4(cos4π/3+isin4π/3)

z2 = 12^1/4cis(4π/3)

8 0
3 years ago
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