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4 years ago

Arrange the following polynomial into descending order and identify the 3rd term.

2 answers:

6 0

Thank you for posting your question here at brainly. Feel free to ask more questions.

The best and most correct answer among the choices provided by the question is 18x.

Hope my answer would be a great help for you.

mart [117]4 years ago

6 0

Answer with Step-by-step explanation:

We are given a polynomial:

$18x + 2x^3 - 3x^2 + 10$

We have to arrange it in descending order and then identify its third term

Polynomial in descending order is:

$2x^3-3x^2+18x+10$

As we can clearly see the third term is:

18x

Hence,

Polynomial in descending order is:

$2x^3-3x^2+18x+10$

and the third term is:

18x

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3 ½ – 2 ⅓ Give your answer as a improper fraction

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4 years ago

Read 2 more answers

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tatyana61 [14]

Answer:

a) $\bar X = 52$

$Median = 55$

b) $Q_1= \frac{44+44}{2}=44$

$Q_3= \frac{57+60}{2}=58.5$

c) $Range = Max -Min = 69-36=33$

d) $s^2 =100.1429$

$s= \sqrt{100.143}=10.0071$

e) $Lower = Q_1 -1.5 IQR = 44-1.5(58.5-44) = 22.25$

$Upper = Q_1 +1.5 IQR = 44+1.5(58.5-44) = 65.75$

A possible outlier would be the value of 69 since its above the upper limti for the boxplot.

Step-by-step explanation:

For this case we have the following dataset:

55 56 44 43 44 56 60 62 57 45 36 38 50 69 65

A total of 15 observations

Part a

We calculate the mean with the following formula:

$\bar X = \frac{\sum_{i=1}^{15} X_i}{15}$

And for this case we got $\bar X = 52$

For the median we ust need to order the data on increasing way like this:

36, 38,43,44,44,45,50,55,56,56,57,60,62,65,69

Since the number of observations is an odd number the median would be on the 8 position from the dataset ordered on this case:

$Median = 55$

Part b

In order to calculate the Q1 we need to select the following data:

36, 38,43,44,44,45,50,55

And the Q1 would be the average between the 4 and 5 positions like this:

$Q_1= \frac{44+44}{2}=44$

And for the Q3 we select these values:

55,56,56,57,60,62,65,69

And the Q3 would be the average between the 4 and 5 positions like this:

$Q_3= \frac{57+60}{2}=58.5$

Part c

The Range is defined as:

$Range = Max -Min = 69-36=33$

Part d

In order to calculate the sample variance we can use the following formula:

$s^2 = \frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}$

And if we replace we got:

$s^2 =100.1429$

And the deviation is just the square root of the variance:

$s= \sqrt{100.143}=10.0071$

Part e

For this case we need to find the lower and upper limits for the boxplot given by:

$Lower = Q_1 -1.5 IQR = 44-1.5(58.5-44) = 22.25$

$Upper = Q_1 +1.5 IQR = 44+1.5(58.5-44) = 65.75$

A possible outlier would be the value of 69 since its above the upper limti for the boxplot.

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4 years ago

Which set of equivalent fractions can be used when adding 7/8 and 5/12 ?

Crazy boy [7]

Answer: 84/96 and 40/96

Step-by-step explanation: You find a denominator that they both have in common. The LCM is 96 and you get the answer! You multiply 1 side by 8 and the other by 12 and you get the answer!

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3 years ago

What is the product? Two-thirds times 12.33 4.11 8.22 24.66 36.99

denis-greek [22]

Answer:

$\frac{2}{3} * 12.33=8.22$