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Gekata [30.6K]
3 years ago
5

Number 11 thanks ASAP ASAP

Mathematics
1 answer:
liq [111]3 years ago
5 0

Answer:

A is the direct variation equation

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Geologists estimate the time since the most recent cooling of a mineral by counting the number of uranium fission tracks on the
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Answer:

(a) The value of P (X = 7) is 0.1388.

(b) The value of P (X ≥ 3) is 0.9380.

(c) The value of P (2 < X < 7) is 0.5433.

(d) \mu_{X}=6

(e) \sigma_{X}=2.45

Step-by-step explanation:

Let <em>X</em> = number of uranium fission tracks on per cm² surface area of the mineral.

The average number of track per cm² surface area is, <em>λ</em> = 6.

The random variable <em>X</em> follows a Poisson distribution with parameter <em>λ</em> = 6.

The probability mass function of a Poisson distribution is:

P(X=x)=\frac{e^{-\lambda}\lambda^{x}}{x!};\ x=0, 1, 2, 3...

(a)

Compute the value of P (X = 7) as follows:

P(X=6)=\frac{e^{-6}(6)^{7}}{7!}=\frac{0.0025\times 279936}{5040}=0.1388

Thus, the value of P (X = 7) is 0.1388.

(b)

Compute the value of P (X ≥ 3) as follows:

P (X ≥ 3) = 1 - P (X < 3)

              = 1 - P (X = 0) - P (X = 1) - P (X = 2)

              =1-\frac{e^{-6}(6)^{0}}{0!}-\frac{e^{-6}(6)^{1}}{1!}-\frac{e^{-6}(6)^{2}}{2!}\\=1-0.00248-0.01487-0.04462\\=0.93803\\\approx0.9380

Thus, the value of P (X ≥ 3) is 0.9380.

(c)

Compute the value of P (2 < X < 7) as follows:

P (2 < X < 7) = P (X = 3) + P (X = 4) + P (X = 5) + P (X = 6)

                   =\frac{e^{-6}(6)^{3}}{3!}+\frac{e^{-6}(6)^{4}}{4!}+\frac{e^{-6}(6)^{5}}{5!}+\frac{e^{-6}(6)^{6}}{6!}\\=0.08924+0.13385+0.16062+0.16062\\=0.54433\\\approx0.5443

Thus, the value of P (2 < X < 7) is 0.5433.

(d)

The mean of the Poisson distribution is:

\mu_{X}=\lambda=6

(e)

The standard deviation of the Poisson distribution is:

\sigma_{X}=\sqrt{\sigma^{2}_{X}}=\sqrt{\lambda}=\sqrt{6}=2.4495\approx2.45

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- In which $6,000 is the balance of credit card at beginning

- The total interest paid over the 03 years is $1,174.44 = $7,174.44 - $6,000

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