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OverLord2011 [107]
3 years ago
5

select the values that make the inequality h/4 greater than or equal to -1 true then write an equivalent inequality in terms of

h

Mathematics
1 answer:
jok3333 [9.3K]3 years ago
3 0

Answer:

Values that make it equal:

-4, -3, -1, 0, 4

Written equivalent inequality:

h≥−4

Step by Step for the written inequality:  

h/4 ≥−1

Multiply both sides by 4. Since 4 is positive, the inequality direction remains the same.

h≥−4

I hope this helps you!! :)

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10
Natasha2012 [34]

Answer:

x= -2

Step-by-step explanation:

Rational Function can be expressed as:

\displaystyle \large{y =  \frac{a}{p(x - b)}  + q}

Where b is our horizontal shift and q is our vertical shift.

For asymptotes, there are two types which are vertical and horizontal.

Vertical Asymtote is the value of -b itself or x = -b.

Therefore, from the functio:

\displaystyle   \large{y =  \frac{10}{x + 2} }

Our vertical asymtote is x = -2

6 0
3 years ago
I don't understand this
timama [110]
The product of 0.02 and 0.7 is 0.014. Notice the additional zero in the number 0.'0'2. Product is the total of two numbers multiplied or times (x).

This is the solution:
0.02
0.7
____
0.014

So the right answer is A. 0.014.
7 0
4 years ago
Read 2 more answers
Help please! (no one was answering it in physics and i really need help)
aivan3 [116]

Let v_0 be the cat's speed just as it leaves the edge of the table. Then taking the point 1.3 m below the edge of the table to be the origin, the cat's horizontal position at time t is given by

x(t)=v_0t

and its height is

y(t)=1.3\,\mathrm m-gt^2

where g is 9.8 m/s^2, the magnitude of the acceleration due to gravity.

The time it takes for the cat to hit the ground is t with

0=1.3\,\mathrm m-gt^2\implies t=\sqrt{\dfrac{1.3\,\rm m}g}\approx0.36\,\mathrm s

(Unfortunately, this doesn't match any of the given options...)

The cat lands 0.75 m away (horizontally) from the edge of the table, so that its speed v_0 was

0.75\,\mathrm m=v_0(0.36\,\mathrm s)\implies v_0\approx2.08\dfrac{\rm m}{\rm s}

(Again, not one of the answer choices...)

I'm guessing there's either a typo in the question or answers.

6 0
3 years ago
(9x-9)(9×+9), your finding the difference between two squares. im have some trouble in how to solve it.​
sergejj [24]

Answer: Your answer is 0 (F.O.I.L) first. outer. inner. last. Or you could use what my teacher calls the magic box

Step-by-step explanation:

So for the boxes you multiply for example the top left box you multiply the 9 above it and the 9 to the left or like the top right box you multiply the -9 above it and the 9 on the outside of the box to the left

8 0
3 years ago
Find a power series representation for the function. (Assume a>0. Give your power series representation centered at x=0 .)
melamori03 [73]

Answer:

Step-by-step explanation:

Given that:

f_x = \dfrac{x^2}{a^7-x^7}

= \dfrac{x^2}{a^7(1-\dfrac{x^7}{a^7})}

= \dfrac{x^2}{a^7}\Big(1-\dfrac{x^7}{a^7} \Big)^{-1}

since  \Big((1-x)^{-1}= 1+x+x^2+x^3+...=\sum \limits ^{\infty}_{n=0}x^n\Big)

Then, it implies that:

\implies  \dfrac{x^2}{a^7} \sum \limits ^{\infty}_{n=0} \Big(\Big(\dfrac{x}{a} \Big)^{^7} \Big)^n

= \dfrac{x^2}{a^7} \sum \limits ^{\infty}_{n=0} \Big(\dfrac{x}{a} \Big)^{^{7n}}

= \dfrac{x^2}{a^7} \sum \limits ^{\infty}_{n=0} \Big(\dfrac{x^{7n}}{a^{7n}} \Big)}

\mathbf{=  \sum \limits ^{\infty}_{n=0} \dfrac{x^{7n+2}}{a^{7n+7}} }}

7 0
3 years ago
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