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erik [133]
2 years ago
11

Gumballs cost $0.50 each and jawbreakers cost $0.30 each bob has 3.00 to spend on candy

Mathematics
1 answer:
Ann [662]2 years ago
4 0

Answer:

Please find attached the required inequality graph created with Microsoft Excel

Step-by-step explanation:

The  cost of each gumball = $0.50

The cost of each jawbreaker = $0.30

The amount Bob has to spend = $3.00

Let x represent the number of gumballs Bob buys and y represent the number jawbreakers Bob buys, we have;

0.50 × x + 0.30 × y ≤ 3.00

0.30 × y ≤ 3.00 - 0.50 × x

y ≤ 3.00/0.3 - 0.50/0.3 × x

y ≤ 10 - 5/3 × x

Therefore, we h

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The table shows the steps for solving the given inequality for x.
slavikrds [6]

Given inequality -3(4-6x) < x+5.

We have -3 in front of Parenthesis.

That represents multiplication of -3 and Parenthesis.

The multiplication of Parenthesis could be done by applying distributive property.

On distributing, we get

-12+18x < x+5

x is added on right side of the inequality. The reverse operation of addition is subtraction. So we need to subtract x from both sides, we get

-12+18x-x < x-x+5

-12+17x < 5

Now, we need to get rid -12 from left side.

So, we need to apply addition property of equality, we need to add 12 on both sides, we get

-12+12+18x < x+5+12

17x < 17

We need to get rid 17 from left side. So we need to apply division property of equality.

On dividing both sides by 17, we get

17x/17 < 17/17

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8 0
3 years ago
Plssss help quick i need it for sum important
Vanyuwa [196]

(a) The product of (2x-4)\ and\ (3x^2-x+4)  is calculated to be =6x^3-14x^2+12x-16

(b)The product of (2x-4) \ and\ (3x^2-x+4)\ is not equal to the product of  (4x-2)\ and\ (3x^2-x+4)

<u>Step-by-step explanation:</u>

<u>(a)</u>

(2x-4)(3x^2-x+4)\\\\=(2x.3x^2)+(2x.-x)+(2x.4)+(-4.3x^2)+(-4.-x)+(-4.4)\\\\=6x^3-2x^2+8x-12x^2+4x-16\\\\=6x^3-14x^2+12x-16

b)

(4x-2)(3x^2-x+4)\\\\=(4x.3x^2)+(4x.-x)+(4x.4)+(-2.3x^2)+(-2.-x)+(-2.4)\\\\=12x^3-4x^2+16x-6x^2+2x-8\\\\=12x^3-10x^2+18x-8

The product of (2x-4) \ and\ (3x^2-x+4)\ is not equal to the product of  (4x-2)\ and\ (3x^2-x+4)

7 0
3 years ago
Find the greates common factor of the following monomials:2r^4s^2 and 36r^4s^3
ki77a [65]

The greatest common factor is 2r^{4} s^{2}


This is because we start by taking the largest factor that goes into both coefficients. Since the first coefficient is 2, we have to try 2 and 1. Since 2 is larger and goes into 36 evenly, we use that.


Then we use the smallest number of each variable. There are 4 r's in both equations. So, that is the number that we take. There are 2 s's in the first term, so we take that number.

6 0
3 years ago
Emanuel was charged \$32$32dollar sign, 32 for a 14\dfrac29 \text{ km}14
Degger [83]

Answer:

2.25

Step-by-step explanation:

because you  have to divide 32 by 14 2/9 resulting in the the 14 2/9 to be 128/9 and then flipped, 9/128. Afterwards, cross out the the 32 and 128 since 32 is a factor of 128 to get 1 and 4.Then apply mutiplication 1/1 * 9/4= 9/4 or 2 1/4= 2.25 

7 0
3 years ago
INSERT TWO RATIONAL NUMBERS BETWEEN 2 AND 3. How to find them?
Kay [80]
There are an infinite number of them.
Here are a few:

2.1
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etc.

How to find them:

You probably never heard this before, but I'll bet
you'll remember it from now on:

<em>ANY number that you can write down on paper completely, </em><em>using digits
and a decimal point if you need it but no symbols, is a rational number.</em>

If you can write it down completely without any 'comments', then it's rational.
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3 years ago
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