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3 years ago

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10 points

1 answer:

natulia [17]3 years ago

4 0

The answer would be B

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A car dealership buys a car for $12,500. They sell the car for $15,750. What is the percent markup?

Elodia [21]

Answer: 26%

Step-by-step explanation:

The formula to calculate the percentage markup is given as:

= Selling price - Cost / Cost price × 100

where selling price = $15750

Cost price = $12500

Percentage markup = ($15750 - $12500) / $12500 × 100

= $3250/$12500 × 100

= 26%

4 0

2 years ago

Read 2 more answers

PLEASE I NEED HELP

notka56 [123]

You would transform 5x + 2x into the same term with the associative property, adding like terms. If you subsitute the different values into the expressions you notice that both have a rate of change of 7 like an arithmetic sequence. To see if any value will make the two expressions equal you make them equal to each other.

5x + 2x = 7x -1

7x = 7x - 1

0 = -1

No they will never have be a solution to both expressions to make them equal because they're parallel to each other.

7 0

3 years ago

Gary wants to buy a video game with a selling price of 48 on sale for 50% off the sales tax in his state is 4.5% how much will G

NeTakaya

Answer:

$25.08

Step-by-step explanation:

48/2= 24(50% of 100% simplifies to 1/2)

24(0.045)=1.08

24 + 1.08 = 25.08

8 0

3 years ago

Simplify the expression 4-(-3)

denpristay [2]

Subtracting a negative is the same as adding it.
4-(-3)=4+3=7

3 0

3 years ago

The length of a 200 square foot rectangular vegetable garden is 4feet less than twice the width. Find the length and width of th

inna [77]

Answer:

Length = 18.099 ft

Width = 11.049 ft

Step-by-step explanation:

let the length of the field be x ft

and the width be y ft

as per the condition given in problem

x=2y-4 -----------(A)

Also the area is given as 200 sqft

Hence

xy=200

Hence from A we get

y(2y-4)=200

taking 2 as GCF out

2y(y-2)=200

Dividing both sides by 2 we get

$y(y-2)=100$

$y^2-2y=100$

subtracting 100 from both sides

$y^2-2y-100=0$

Now we solve the above equation with the help of Quadratic formula which is given in the image attached with this for any equation in form

$ax^2+bx+c=0$

Here in our case

a=1

b=-1

c=-100

Putting those values in the formula and solving them for y

$y=\frac{-(-2)+\sqrt{(-2)^2-4 \times (-1) \times 100}}{2 \time 1}$

$y=\frac{-(-2)-\sqrt{(-2)^2-4 \times (-1) \times 100}}{2 \time 1}$

Solving first

$y=\frac{2+\sqrt{4+400}{2}$

$y=\frac{2+\sqrt{404}{2}$

$y=\frac{2+20.099}{2}$

$y=\frac{22.099}{2}$

$y=11.049$

Solving second one

$y=\frac{-(-2)-\sqrt{(-2)^2-4 \times (-1) \times 100}}{2 \time 1}$

$y=\frac{2-\sqrt{4+400}{2}$

$y=\frac{2-\sqrt{404}{2}$

$y=\frac{2-20.099}{2}$

$y=\frac{-18.99}{2}$

$y=-9.045$

Which is wrong as the width can not be in negative

Our width of the field is

y=11.099

Hence the length will be

x=2y-4

x=2(11.049)-4

x=22.099-4

x=18.099

Hence our length x and width y :

Length = 18.099 ft

Width = 11.049 ft

4 0

3 years ago