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3 years ago

6x + 15xy Looking For Factor

Mathematics

1 answer:

padilas [110]3 years ago

6 0

Answer:

x(6 + 15y)

Step-by-step explanation:

In this instance, you can divide by a factor of x.

6x/x = 6

15xy/x = 15y

Therefore, we are left with 6 + 15y.

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I will give you branilest!

xxMikexx [17]

Answer:

When simplified they all are 1/5

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3 years ago

What is the derivative of 2te^-t

Sveta_85 [38]

$(2te^{-t})'=(2t)'e^{-t}+2t(e^{-t})'=2e^{-t}+2t(-e^{-t})=2e^{-t}-2te^{-t}$

6 0

3 years ago

How do you write this in standard form? (6-7i)/(1-2i)

xenn [34]

$\frac { \left( 6-7i \right) }{ \left( 1-2i \right) } \cdot 1\\ \\ =\frac { \left( 6-7i \right) }{ \left( 1-2i \right) } \cdot \frac { \left( 1+2i \right) }{ \left( 1+2i \right) } \\ \\ =\frac { 6+12i-7i-14{ i }^{ 2 } }{ 1+2i-2i-4{ i }^{ 2 } }$

$\\ \\ =\frac { 6+5i-14\left( -1 \right) }{ 1-4\left( -1 \right) } \\ \\ =\frac { 6+5i+14 }{ 1+4 } \\ \\ =\frac { 20+5i }{ 5 } \\ \\ =\frac { 20 }{ 5 } +\frac { 5i }{ 5 } \\ \\ =4+i$

8 0

3 years ago

What is the distance between the points (2, 10) and (-6, 4) on the coordinate plane?

Galina-37 [17]

It's 3/4 because (y2-y1)/(x2-x1)

3 0

3 years ago

(2) Using the distance formula, d = √(x2 - x1)2 + (y2 - y1)2, what is the distance between point (-2, 2) and point (4, 4) rounde

monitta

Using the distance formula, $d = \sqrt{(x_{2} - x_{1})^2 + (y_{2} - y_{1})^2 } \\$ , what is the distance between point (-2, 2) and point (4, 4) rounded to the nearest tenth?

Using the points given, plug them into the equation.

$d = \sqrt{(x_{2} - x_{1})^2 + (y_{2} - y_{1})^2 } \\d = \sqrt{((4) - (-2))^2 + ((4) - (2)^2 } \\d=\sqrt{(4+2)^2 + (4-2)^2}\\d=\sqrt{(6)^2 + (2)^2} \\d=\sqrt{36+4} \\d=\sqrt{40} \\$

Plug this into a calculator and you get 6.32455532

Since you only need it up to the tenth (0.1), round up 6.32

Since two is lower than four, we drop it.

Therefore, the distance between points (-2, 2) and (4, 4) is 6.3

Hope this helps ^w^

8 0

3 years ago