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valentinak56 [21]
3 years ago
13

Simplify the expression 3^5*6^-6/3^3*6^-4 A. 180 B. 5/2 C. 1/4 D. 3/20

Mathematics
1 answer:
adelina 88 [10]3 years ago
6 0
<span>3^5*6^-6/3^3*6^-4
= 3^(5-3) 6^(-6+4)
=3^2 6^-2
= 9/36
= 1/4

answer


</span><span>C. 1/4</span>
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2:x and 12:18 a-3, b-4, c-6
nirvana33 [79]

The Corrected Problem is :

2:x and 12:18 identify the value of x that makes each pair of ratios equivalent .

Solution:

If a pair of Ratios are equivalent then we can write

\frac{2}{x}=\frac{12}{18}\\ \\ \text{Simplify we get}\\ \\ 12x=36\\ \\ \text{Divide both the sides by 12 we get}\ \\ \\ \frac{12x}{12}=\frac{36}{12}\\ \\  x=3\\ \\ \text{Hence the required value of x is 3}\\

3 0
3 years ago
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Evaluate - (2-6)(23).<br> O A. 8<br> O B.<br> 1<br> 8<br> Oc.<br> 1<br> 8<br> D. -8
kumpel [21]

Answer:

-92.

Step-by-step explanation:

2 - 6 is -4.

-4 x 23 is -92.

7 0
3 years ago
Please? I need help here
Yuki888 [10]

Answer:

<h2>D</h2>

Step-by-step explanation:

If pair of ratios does form a true proportion then:

a:b=c:d\to\dfrac{a}{b}=\dfrac{c}{d}\to ad=bc

A)\\\\8:14=20:35\to\dfrac{8}{14}=\dfrac{20}{35}\\\\(8)(35)=(14)(25)\\\\280=280\qquad\bold{TRUE}\\\\b)\\\\\dfrac{6}{10}=\dfrac{15}{25}\\\\(6)(25)=(10)(15)\\\\150=150\qquad\bold{TRUE}

c)\\\\\dfrac{9}{5}=\dfrac{27}{15}\\\\(9)(15)=(5)(27)\\\\135=135\qquad\bold{TRUE}\\\\d)\\\\12:15=30:50\to\dfrac{12}{15}=\dfrac{30}{50}\\\\(12)(50)=(15)(30)\\\\600=450\qquad\bold{FALSE}

3 0
3 years ago
You are buying boxes of cookies at a bakery. Each box of cookies costs 4 dollars. In the equation below, c represents the number
Yuliya22 [10]
What the answer you want to find out ?
7 0
3 years ago
Brass is made from a mixture of copper and other elements. a mixture that is 80% copper is combined with a mixture that is 60% c
algol [13]

The equation that can be used to find x, the amount of the 60% mixture used to create the 65% mixture is:

0.60*x + 0.80*(100 - x) = 0.65*(100).    

<h3>Which equation we should use?</h3>

First, let's define two variables:

  • x = pounds of the 60% copper brass.
  • y = pounds of the 80% copper brass.

We know that we want to make 100 lb of 65% copper brass, then we must have that:

x + y = 100

And the percentage of copper before and after mixing must be the same, so we can write:

0.60*x + 0.80*y = 0.65*(x + y).

(where the percentages are written in decimal form).

Then we have a system of equations:

x + y = 100

0.60*x + 0.80*y = 0.65*(x + y).

To get a single equation, we can isolate the variable "y" on the first equation:

y = 100 - x

Now we replace that in the other equation:

0.60*x + 0.80*(100 - x) = 0.65*(100).      

This is what we wanted to get, an equation that can be used to find x, the amount of the 60% mixture used to create the 65% mixture.

If you want to learn more about systems of equations:

brainly.com/question/13729904

#SPJ1

4 0
2 years ago
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