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djverab [1.8K]
2 years ago
15

Please help, if you don’t know, don’t answer.

Mathematics
2 answers:
Novosadov [1.4K]2 years ago
8 0

Answer:

The answer is 1.

Step-by-step explanation:

Dominik [7]2 years ago
3 0
If this is what you mean- -4•-9= positive 36
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13 14<br> x<br> 7 11<br> What is 13/7 times 14/11 equal
Ostrovityanka [42]

Answer:

(2 × 7 × 13) / (7 × 11) =

((2 × 7 × 13) ÷ 7) / ((7 × 11) ÷ 7) =

(2 × 7 ÷ 7 × 13)/(7 ÷ 7 × 11) =

(2 × 1 × 13)/(1 × 11) =

(2 × 13)/11 =

26/11;

Step-by-step explanation:

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3 years ago
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Answer:

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Step-by-step explanation:

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2 years ago
Which equation has a graph that is perpendicular to the graph of -x + 6y = -12?
serious [3.7K]

Answer:

c) 6x + y = -52  is required equation perpendicular to the given equation.

Step-by-step explanation:

If the equation is of the form    : y = mx  + C.

Here m = slope of the equation.

Two equations are said to be perpendicular if the product of their respective slopes is -1.

Here, equation 1 :  -x + 6y = -12

or, 6y = -12  + x

or, y = (x/6)  - 2

⇒Slope of line 1 = (1/6)

Now, for equation 2  to be  perpendicular:

Check for each equation:

a. x + 6y = -67       ⇒  6y = -67  - x

or, y = (-x/6)  - (67/6)      ⇒Slope of line 2 = (-1/6)

but \frac{1}{6} \times \frac{-1}{6}  \neq -1

b. x - 6y = -52   ⇒  -6y = -52  - x

or, y = (x/6)  + (52/6)      ⇒Slope of line 2 = (1/6)

but \frac{1}{6} \times \frac{1}{6}  \neq -1

c. 6x + y = -52    

or, y =y = -52  - 6x      ⇒Slope of line 2 = (-6)

\frac{1}{6} \times (-6)  =  -1

Hence, 6x + y = -52  is required equation 2.

d. 6x - y = 52  ⇒  -y = 52  - 6x

or, y = 6x   - 52      ⇒Slope of line 2 = (6)

but \frac{1}{6} \times 6  \neq -1

Hence,  6x + y = -52  is  the  only required equation .

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3 years ago
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