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3 years ago

Can someone help with this math word problem.

Mathematics

1 answer:

iragen [17]3 years ago

7 0

Answer:

Step-by-step explanation:

Time taken to eat the pizza in seconds =28×60=1680 seconds

If it takes 20seconds to lift, bite and chew,

Then the total bites taken to finish the pizza =1680/20 =84 bites

If for each bite 9cm² disappeared, then area that disappeared for 84bites =84×9cm² = 756cm²

Total area of pizza =756cm²

If area =(πd²)/4,

Then d² =(4×A)/π

d²=4×756/3.14=963.06

d=√963.06 = 31.03cm

1 centimeter=0.394inches

31.03cm= 0.394×31.03=12.23 inches ≈ 12inches(to the nearest inch)

The diameter of the pizza is 12inches

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A ½in diameter rod of 5in length is being considered as part of a mechanical linkagein which it can experience a tensile loading

Evgesh-ka [11]

Answer:

a. Maximum Load = Force = 27085.09 N

b. Maximum Energy = 3.440 Joules

Step-by-step explanation:

Given

Rod diameter = ½in = 0.5in

Length = 5in

Young's modulus = 15.5Msi

By applying the 0.2% offset rule,

The maximum load the rod can hold before it gets to breaking point is given as follows by taking the strain as 0.2%

Young Modulus = Stress/Strain ------- Make Stress the Subject of Formula

Stress = Strain * Young Modulus

Stress = 0.2% * 15.5

Stress = 0.002 * 15.5

Stress = 0.031Msi

Calculating the area of the rod

Area = πr² or πd²/4

Area, A = 22/7 * 0.5^4 / 4

A = 22/7 * 0.25 / 4

A = 5.5/28

A = 0.1964in²

The maximum load that the rod would take before it starts to permanently elongate is given by

Force = Stress * Atea

Force = 0.031Msi * 0.1964in²

Force = 31Ksi * 0.1964in²

Force = 6.089Ksi in²

Force = 6.089 * 1000lbf

Force = 6089 lbf

1 lbf = 4.4482N

So, Force = 6089 * 4.4482N

Force = 27085.09 N

Using Strain to Energy Formula

U = V×σ²/2·E

Where V = Volume

V = Length * Area

V = 5 in * 0.1964in²

V = 0.982in³

σ = Stress = 0.031Msi

= 0.031 * 1000Ksi

= 31Ksi

= 31 * 1000psi

= 31000psi

E = Young Modulus = 15.5Msi

= 15.5 * 1000Ksi

= 15.5 * 1000 * 1000psi

= 15500000psi

So,

Energy = 0.982 * 31000²/ ( 2 * 15500000)

Energy = 943,702,000/31000000

Energy = 30.442in³psi

------- Converted to ftlbf

Energy = 2.537 ftlbf

-------- Converted to Joules

Energy = 3.440 Joules

7 0

4 years ago

Change -2-3 into addition problem<br><img src="https://tex.z-dn.net/?f=%28%20-%202%20-%203%20%3D%20" id="TexFormula1" title="( -

SashulF [63]

Answer: - (2 + 3) = -5

<u>Step-by-step explanation:</u>

When combining numbers that have the same sign, you add them and then include the sign.

For example:

-2 - 3 = -(2 + 3) = -5

-6 - 5 = -(6 + 5) = -11

-7 - 8 = -(7 + 8) = -15

8 0

3 years ago

Read 2 more answers

A blimp is providing aerial television views of a football game. The television camera sights the stadium at a 7 degree angle of

levacccp [35]

The line of sight is the hypotenuse of a right triangle with short leg 400 m, 90 degree angle where the short leg meets the ground, an 83 degree angle at the top, and a 7 degree angle across from the right angle on the ground. Because this 7 degree angle is an alternate interior angle with the angle of depression, they are the same degree measure. Looking for the hypotenuse, we use the sin ratio: sin (7) = 400/x.

8 0

3 years ago

An aeroplane X whose average speed is 50°km/hr leaves kano airport at 7.00am and travels for 2 hours on a bearing 050°. It then

Zigmanuir [339]

Answer:

(a)123 km/hr

(b)39 degrees

Step-by-step explanation:

Plane X with an average speed of 50km/hr travels for 2 hours from P (Kano Airport) to point Q in the diagram.

Distance = Speed X Time

Therefore: PQ =50km/hr X 2 hr =100 km

It moves from Point Q at 9.00 am and arrives at the airstrip A by 11.30am.

Distance, QA=50km/hr X 2.5 hr =125 km

Using alternate angles in the diagram:

$\angle Q=110^\circ$

(a)First, we calculate the distance traveled, PA by plane Y.

Using Cosine rule

$q^2=p^2+a^2-2pa\cos Q\\q^2=100^2+125^2-2(100)(125)\cos 110^\circ\\q^2=34175.50\\q=184.87$ km$

SInce aeroplane Y leaves kano airport at 10.00am and arrives at 11.30am

Time taken =1.5 hour

Therefore:

Average Speed of Y

$=184.87 \div 1.5\\=123.25$ km/hr\\\approx 123$ km/hr (correct to three significant figures)$

(b)Flight Direction of Y

Using Law of Sines

$\dfrac{p}{\sin P} =\dfrac{q}{\sin Q}\\\dfrac{125}{\sin P} =\dfrac{184.87}{\sin 110}\\123 \times \sin P=125 \times \sin 110\\\sin P=(125 \times \sin 110) \div 184.87\\P=\arcsin [(125 \times \sin 110) \div 184.87]\\P=39^\circ $ (to the nearest degree)$

The direction of flight Y to the nearest degree is 39 degrees.

7 0

3 years ago

Can a ray be bisected?

34kurt

Such a ray that divides an angle into two equal angles is called an angle bisector.

Likewise, two rays that divide an angle into three congruent angles are called angle trisectors. Figure %:

An angle bisected and trisected On the left, angle ABC is bisected by the ray BD.

Credits to google.

In short, no.

8 0

3 years ago