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2 years ago

Could anyone help me with this?

Mathematics

1 answer:

inn [45]2 years ago

5 0

Answer:

93.4 cm²

Step-by-step explanation:

Area of the shaded region = area of the square - area of half of the circle

Area of the shaded region = s² + ½(πr²)

Where,

r = 6.2 cm

s = length of square = diameter of circle = 2*r = 2*6.2

s = 12.4 cm

Plug in the values

Area of the shaded region = 12.4² - ½(π × 6.2²)

= 153.76 - 60.381411

= 93.378589

≈ 93.4 cm² (nearest tenth)

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$A' = \frac{x}{8} - \frac{\sqrt {3} \ (8-x)}{2} = 0\\\\\frac{x}{8} - \frac{8\sqrt{3} -\sqrt{3} x}{2} =0\\\\x - 4(8\sqrt{3} -\sqrt{3}x)=0\\\\x-32\sqrt3 - 4\sqrt3 x = 0\\\\x - 4\sqrt3 = 32 \sqrt3 \\\\(1 - 4\sqrt3)x = 32 \sqrt3 \\\\x = \frac{32 \sqrt3 }{(1 - 4\sqrt3)}\\\\x =6.99 \approx 7.00$

We find $A''(7)$ to check whether $x = 7$ is the minimum or maximum of the function.

$A'' = \frac {1}{8} +\frac {\sqrt {3}}{2} \\\\A'' = 0.99 \approx 1.00$

Hence, $x = 7$ is the minimum and $x = 8$ will be the maximum

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