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Orlov [11]
3 years ago
6

Para hacer 600 m de una obra, 30 obreros han trabajado 12 dias a razon de 10 horas diarias. ¿Cuantos dias necesitaran 36 obreros

para hacer 900 m de la obra trabajando 6 horas diarias?
Mathematics
1 answer:
Gwar [14]3 years ago
7 0

Respuesta:

25 días

Explicación paso a paso:

Dado :

escenario 1

Área = 600 m

Número de días = 12

Número de trabajadores = 30

Tasa = 6

Escenario 2:

Área = 900 m

Número de días = n

Número de trabajadores = 36

Tasa = 6

Igualar los parámetros en cada escenario:

12 / n = 36/30 * 6/10 * 600/900

12 / n = 6/5 * 3/5 * 2/3

12 / n = 6/5 * 1/5 * 2/1

12 / n = 12/25

12 * 25 = 12n

300 = 12n

n = 300/12

n = 25 días

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The z score probability distribution for sample average is given by;

               Z = \frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } } ~ N(0,1)

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           \sigma  = standard deviation = 0.85

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(b) Probability that sample average sediment density is between 2.65 and 3.00 is given by = P(2.65 < X bar < 3.00) = P(X bar < 3) - P(X bar <= 2.65)

P(X bar < 3) = P( \frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } } < \frac{3-2.65}{\frac{0.85}{\sqrt{25} } } ) = P(Z < 2.06) = 0.98030

 P(X bar <= 2.65) = P( \frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } } <= \frac{2.65-2.65}{\frac{0.85}{\sqrt{25} } } ) = P(Z <= 0) = 0.5

Therefore, P(2.65 < X bar < 3)  = 0.98030 - 0.5 = 0.4803 .

                                                                             

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