4x + 2y = 8 (1)
8x + 4y = -4y (2)
A) Two lines are parallel if they have the same gradient
- putting both equations into the gradient- intercept form ( y = mx + c where m is the gradient)
(1) 4x + 2y = 8
2y = 8 - 4x
y = -2x + 4
(2) 8x + 4y = -4y
<span> </span>8x = -4y - 4y
y =

y = -x
<span>
Thus the gradient of the two equations are different and as such the two lines are not parallel</span>
B) When two lines are perpendicular, the product of their gradient is -1

p = (-2) * (-1)
p = 2
<span> ∴
the two lines are not perpendicular either.</span>
Thus these lines are SKEWED LINES
Answer:
-x^2-2x-3
Step-by-step explanation:
- Question 1: Just substitute in the values of f(x) and g(x) and simplify!
- f(x) - g(x) = 4x^2-5x+3-(5x^2-3x+6)
- f(x)-g(x) = 4x^2-5x+3-5x^2+3x-6
- f(x)-g(x) = -x^2-2x-3
Tell me if this helps, and if you still need number 2 or if you can do it by yourself! (Hint: substituting also plays a role in question number 2.)
Hope this helps!!
Answer:
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Step-by-step explanation:
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Answer:
Bar chart
Step-by-step explanation:
easier to understand