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EleoNora [17]
3 years ago
12

Figure B is a scaled copy of Figure A.

Mathematics
1 answer:
dlinn [17]3 years ago
4 0

Answer:1/3

Step-by-step explanation:

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How to solve right triangles
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Subtract one side from 90 and get the other side
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Last season, two running backs on the Steelers
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Step-by-step explanation:

Last season two running backs on the Steelers football team rushed a combined total of 1550 yards.  One rushed 4 times as many yards as the other.  Let x and y represent the number of yards each individual player rushed. this is the equation that was used

         x + y = 1550

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2 years ago
Felicia’s mother is four times as old as Felicia. In 16 years, her mother will be twice her age. How old is Felicia now?
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16

Step-by-step explanation:

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Read 2 more answers
A steady wind blows a kite due west. The kite's height above ground from horizontal position x = 0 to x = 80 ft is given by y =
GaryK [48]

Answer:

The distance travelled by the kite is 122.8 ft ( approx )

Step-by-step explanation:

Here, the given function,

y=150-\frac{1}{40}(x-50)^2

Differentiating with respect to x,

y'=-\frac{1}{20}(x-50)

∵ arc length of a curve is,

L=\int_{a}^{b} \sqrt{1+y'^2}dx

Where, y shows the height of the curve for a ≤ x ≤ b,

Thus, the arc length of the given curve is,

L=\int_{0}^{80} \sqrt{1+(-\frac{1}{20}(x-50)^2}dx

Put -\frac{1}{20}(x-50)=tan\theta

\implies -dx=-20 sec^2\theta d\theta

\implies L=-20\int_{0}^{80} \sqrt{1+tan^2\theta}sec^2\theta d\theta

=-20\int_{0}^{80} (sec \theta ) sec^2\theta d\theta

=-20\int_{0}^{80} (sec \theta ) sec^2\theta d\theta

By integration by parts,

=|-\frac{20}{2}(sec \theta tan\theta +ln|sec\theta +tan\theta |) |^{x=80}_{x=0}

If x = 80, tan \theta = -\frac{1}{20}(30-50)=\frac{3}{2}

sec \theta = \frac{\sqrt{13}}{2}

\implies \theta = \frac{1}{20}(0-50)=\frac{5}{2}

sec \theta = \frac{\sqrt{29}}{2}

Thus, the length of the curve is,

=-10(\frac{\sqrt{13}}{2}(-\frac{3}{2}) +ln|\frac{13}{2}-\frac{3}{2}|) + 10(\frac{5\sqrt{29}}{4} + ln |\frac{29}{2} + \frac{5}{2} |)

\approx 122.8\text{ feet}

8 0
3 years ago
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