The prime number is 53 because the others have factors other than itself and 1 but 53 doesn't
Answer:
5 hours 22 minutes
Step-by-step explanation:
Let us represent the number of hours that Jeri worked as: h
Jeri's lawn service charges an initial fee of $4.50 plus $3 an hour
= $4.50 + $3 × h
= $4.50 + 3h
If she is asked to start before 7 a.m. Jeri charges 1.5 times the regular amount.
= 1.5 × ($4.50 + 3h)
If she made $29.25 on a job that began at 5 am, how many hours did Jeri work?
Hence, we have the final equation;
= 1.5 × ($4.50 + 3h) = $29.25
= 6.75 + 4.5h = 29.25
Collect like terms
= 4.5h = 29.25 - 6.75
4.5h = 22.5
h = 22.5/4.5
h = 5.3571428571
Approximately= 5.36 hours
1 hour = 60 minutes
0.36 hour =
60 × 0.36
= 21.6 minutes
Approximately ≈ 22 minutes
Therefore, Jeri worked for 5 hours 22 minutes
Round about...90 feet per second
Using a discrete probability distribution, it is found that:
a) There is a 0.3 = 30% probability that he will mow exactly 2 lawns on a randomly selected day.
b) There is a 0.8 = 80% probability that he will mow at least 1 lawn on a randomly selected day.
c) The expected value is of 1.3 lawns mowed on a randomly selected day.
<h3>What is the discrete probability distribution?</h3>
Researching the problem on the internet, it is found that the distribution for the number of lawns mowed on a randomly selected dayis given by:
Item a:
P(X = 2) = 0.3, hence, there is a 0.3 = 30% probability that he will mow exactly 2 lawns on a randomly selected day.
Item b:

There is a 0.8 = 80% probability that he will mow at least 1 lawn on a randomly selected day.
Item c:
The expected value of a discrete distribution is given by the <u>sum of each value multiplied by it's respective probability</u>, hence:
E(X) = 0(0.2) + 1(0.4) + 2(0.3) + 3(0.1) = 1.3.
The expected value is of 1.3 lawns mowed on a randomly selected day.
More can be learned about discrete probability distributions at brainly.com/question/24855677