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dlinn [17]
2 years ago
5

Complete the solution of the equation. Find the value of Y when X equals 5. X-5y=45

Mathematics
2 answers:
bearhunter [10]2 years ago
8 0

Answer:

y = -8

Step-by-step explanation:

5 - 5y = 45

-5y = 40

y = -8

Ivan2 years ago
6 0

Answer:

-8

Step-by-step explanation:

replace X with 5

subtract 5 from both sides of the equation:

-5y = 40

divide by - 5

y = -8

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126/6=21 so your answer is 21 ! lol 
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Plz help...................
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The prime number is 53 because the others have factors other than itself and 1 but 53 doesn't
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Jeri's lawn service charges an initial fee of $4.50 plus $3 an hour. If she is asked to
STALIN [3.7K]

Answer:

5 hours 22 minutes

Step-by-step explanation:

Let us represent the number of hours that Jeri worked as: h

Jeri's lawn service charges an initial fee of $4.50 plus $3 an hour

= $4.50 + $3 × h

= $4.50 + 3h

If she is asked to start before 7 a.m. Jeri charges 1.5 times the regular amount.

= 1.5 × ($4.50 + 3h)

If she made $29.25 on a job that began at 5 am, how many hours did Jeri work?

Hence, we have the final equation;

= 1.5 × ($4.50 + 3h) = $29.25

= 6.75 + 4.5h = 29.25

Collect like terms

= 4.5h = 29.25 - 6.75

4.5h = 22.5

h = 22.5/4.5

h = 5.3571428571

Approximately= 5.36 hours

1 hour = 60 minutes

0.36 hour =

60 × 0.36

= 21.6 minutes

Approximately ≈ 22 minutes

Therefore, Jeri worked for 5 hours 22 minutes

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3 years ago
A car is traveling 60 mi per hour what is the cars speed in ft per second
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100 Brainliest up for grabs to person who can answer all of these with no links:
kogti [31]

Using a discrete probability distribution, it is found that:

a) There is a 0.3 = 30% probability that he will mow exactly 2 lawns on a randomly selected day.

b) There is a 0.8 = 80% probability that he will mow at least 1 lawn on a randomly selected day.

c) The expected value is of 1.3 lawns mowed on a randomly selected day.

<h3>What is the discrete probability distribution?</h3>

Researching the problem on the internet, it is found that the distribution for the number of lawns mowed on a randomly selected dayis given by:

  • P(X = 0) = 0.2.
  • P(X = 1) = 0.4.
  • P(X = 2) = 0.3.
  • P(X = 3) = 0.1.

Item a:

P(X = 2) = 0.3, hence, there is a 0.3 = 30% probability that he will mow exactly 2 lawns on a randomly selected day.

Item b:

P(X \geq 1) = 1 - P(X = 0) = 1 - 0.2 = 0.8

There is a 0.8 = 80% probability that he will mow at least 1 lawn on a randomly selected day.

Item c:

The expected value of a discrete distribution is given by the <u>sum of each value multiplied by it's respective probability</u>, hence:

E(X) = 0(0.2) + 1(0.4) + 2(0.3) + 3(0.1) = 1.3.

The expected value is of 1.3 lawns mowed on a randomly selected day.

More can be learned about discrete probability distributions at brainly.com/question/24855677

6 0
2 years ago
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