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pickupchik [31]
3 years ago
14

If you roll a 6-sided die 4 times, what is the probability of one roll being a multiple of 3? A)2/3 B)16/81 C)145/1296 D)65/81 E

)625/1296 (I really need help! Pls answer fast!)
Mathematics
2 answers:
kvasek [131]3 years ago
8 0

Answer:

671/1296

Step-by-step explanation:

DerKrebs [107]3 years ago
4 0

Answer:

671/1296

The probability of rolling at least one six is therefore 1 − 625/1296 = 671/1296 ≈ . 517.

Step-by-step explanation:

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Step-by-step explanation:

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Factor completely: 4a^2+b^2−c^2+4ab
Lapatulllka [165]

Answer:

4a^{2} + b^{2}  - c^{2}  + 4ab = (2a + b -c) (2a + b+c)

Step-by-step explanation:

Here, the given expression is 4a^{2} + b^{2}  - c^{2}  + 4ab

or, the given expression can be written as

 (4a^{2} + b^{2}  + 4ab ) - c^{2}

Now, by ALGEBRAIC IDENTITY: (x+y)^{2}  = x^{2} + y^{2}  + 2xy

So, similarly here, (2a +b){2}  = 4a^{2} + b^{2}  + 4ab

Hence, on simplification, the expression

(4a^{2} + b^{2}  + 4ab ) - c^{2} = (2a + b)^{2} - c^{2}

Now, by ALGEBRAIC IDENTITY: (x +y)(x-y) = x^{2}  - y^{2}

So, similarly  (2a + b)^{2} - c^{2}= (2a + b -c) (2a + b+c)

Hence, the given expression is factorized as:

4a^{2} + b^{2}  - c^{2}  + 4ab = (2a + b -c) (2a + b+c)

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