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pickupchik [31]
3 years ago
14

If you roll a 6-sided die 4 times, what is the probability of one roll being a multiple of 3? A)2/3 B)16/81 C)145/1296 D)65/81 E

)625/1296 (I really need help! Pls answer fast!)
Mathematics
2 answers:
kvasek [131]3 years ago
8 0

Answer:

671/1296

Step-by-step explanation:

DerKrebs [107]3 years ago
4 0

Answer:

671/1296

The probability of rolling at least one six is therefore 1 − 625/1296 = 671/1296 ≈ . 517.

Step-by-step explanation:

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mina [271]

a) Since both limits are <em>distinct</em> and do not exist, we conclude that x = - 1 is not part of the domain of the <em>rational</em> function.

b) The function f(x) = \frac{x}{x^{2}+ x} is equivalent to the function g(x) = \frac{1}{x + 1}.

<h3>How to determine whether a limit exists or not</h3>

According to theory of limits, a function f(x) exists for x = a if and only if \lim_{x\to a^{-}} f(x) = \lim_{x \to a^{+}} f(x). This criterion is commonly used to prove continuity of functions.

<em>Rational</em> functions are not continuous for all value of x, as there are x-values that make denominator equal to 0. Based on the figure given below, we have the following <em>lateral</em> limits:

\lim_{x \to -1^{-}} \frac{x}{x^{2}+x} = - \infty

\lim_{x \to -1^{+}} \frac{x}{x^{2}+x} = + \infty

Since both limits are <em>distinct</em> and do not exist, we conclude that x = - 1 is not part of the domain of the <em>rational</em> function.

In addition, we can simplify the function by <em>algebra</em> properties:

\frac{x}{x^{2}+ x} = \frac{x}{x\cdot (x + 1)} = \frac{1}{x + 1}

g(x) = \frac{1}{x + 1}

The function f(x) = \frac{x}{x^{2}+ x} is equivalent to the function g(x) = \frac{1}{x + 1}.

To learn more on lateral limits: brainly.com/question/21783151

#SPJ1

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2 years ago
The population of Springdale increased by 20% in ten years. The population now is 24,000 people. What was the population ten yea
Dahasolnce [82]
120000 is your answer because if you go to a calculator and type in 24000 divided by 20% then it will give you 120000.
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4 years ago
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