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3 years ago

HELPPPPPPP!!!!!! i need this today

Mathematics

1 answer:

Jet001 [13]3 years ago

3 0

Answer:

(d) 78√3

hope it is right answer for it !!

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Click the link, Thank you. :D

sashaice [31]

The answer is 104,975. If you multiply 95 by 17 by 65, you'll get your answer. Hope this helps!

7 0

3 years ago

Read 2 more answers

Whitch of the following is closest to 8 62 61 65 66

Natasha2012 [34]

Answer:

If the question is which is closest to 8, the answer is 61

Step-by-step explanation:

6 0

2 years ago

PLZ HELP I NEED IT RN OR IMMA FAIL BADLY NO DOWNLOADS PLZ

Lapatulllka [165]

Answer:

A. Point A is the correct answer

8 0

3 years ago

Read 2 more answers

I write out all the whole numbers, starting from 1. If I wrote 1994 digits altogether, what was the last complete number I wrote

Nataly_w [17]

Answer:

You wrote the numbers from 1 to 9: 9 digits.

You wrote the numbers from 10 to 99: 90*2 = 180 digits.

You have written 189 digits.

Then you wrote another 1994 - 189 = 1805

All the numbers from 100 to 999 have 3 digits

So you wrote 1805/3 = 601 2/3

This means 601 full numbers and 2 digits from the 602. number.

So 100 + 601 - 1 = 700 was the last number you wrote.

Do you agree?

3 0

3 years ago

A food company sells salmon to various customers. The mean weight of the salmon is 37 lb with a standard deviation of 2 lbs. The

brilliants [131]

Answer:

The standard deviation for the mean weigth of Salmon is 2/3 lbs for restaurants, 2/7 lbs for grocery stores and 1/4 lbs for discount order stores.

Step-by-step explanation:

The mean sample of the sum of n random variables is

$\overline{X} = \frac{X_1+X_2+...+X_n}{n}$

If $X_1, ..., X_n$ are indentically distributed and independent, like in the situation of the problem, then the variance of $X_1 + .... + X_n$ will be the sum of the variances, in other words, it will be n times the variance of $X_1$ .

However if we multiply this mean by 1/n (in other words, divide by n), then we have to divide the variance by 1/n², thus $\overkine{X} = \frac{V(X_1)}{n}$ and as a result, the standard deviation of $\overline{X}$ is the standard deviation of $X_1$ divided by $\sqrt{n}$ .

Since the standard deviation of the weigth of a Salmon is 2 lbs, then the standard deviations for the mean weigth will be:

Restaurants: We have boxes with 9 salmon each, so it will be $\frac{2}{\sqrt{9}} = \frac{2}{3}$
Grocery stores: Each carton has 49 salmon, thus the standard deviation is $\frac{2}{\sqrt{49}} = \frac{2}{7}$
Discount outlet stores: Each pallet has 64 salmon, as a result, the standard deviation is $\frac{2}{\sqrt{64}} = \frac{1}{4}$

We conclude that de standard deivation of the mean weigth of salmon of the types of shipment given is: 2/3 lbs for restaurants, 2/7 lbs for grocery stores and 1/4 lbs for discount outlet stores.

7 0

3 years ago