Answer: 49
Step-by-step explanation:
From your question, I think you mean the largest number. The answer is given below.
Let the five consecutive odd numbers be:
a, a+2, a+4, a+6 and a+8.
Thee sum of the first and double the last is 139. This can be written as:
a + 2(a+8) = 139
a + 2a + 16 = 139
3a + 16 = 139
3a = 139 - 16
3a = 123
a = 123/3
a = 41
The first number = 41
The largest number = a+8 = 41 + 8 = 49.
Answer:
x² - 10x + 34
Step-by-step explanation:
given the roots are x = 5 ± 3i then the factors are
(x - (5 + 3i))(x - (5 - 3i))
= (x - 5)² - 9i² ← expand (x - 5)²
= x² - 10 x + 25 + 9 → [ i² = - 1 ]
= x² - 10x + 34
the missing term is 10x
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Basically, what this asks you is to maximize the are A=ab where a and b are the sides of the recatangular area (b is the long side opposite to the river, a is the short side that also is the common fence of both corrals). Your maximization is constrained by the length of the fence, so you have to maximize subject to 3a+b=450 (drawing a sketch helps - again, b is the longer side opposite to the river, a are the three smaller parts restricting the corrals)
3a+b = 450
b = 450 - 3a
so the maximization max(ab) becomes
max(a(450-3a)=max(450a-3a^2)
Since this is in one variable, we can just take the derivative and set it equal to zero:
450-6a=0
6a=450
a=75
Plugging back into b=450-3a yields
b=450-3*75
b=450-225
b=215
Hope that helps!
Answer:
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