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2 years ago

9

So to celebrate my actual return and to start drama (kinda)What is 3+3x3-3x3+3+3+3x3-17

1 answer:

Leya [2.2K]2 years ago

7 0

I think it’s 1
?

explanations

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Do you know parallelogram WXYZ Parkway 270° around point W what will be the length of the image WZ

Lerok [7]

Answer:

5 units

Step-by-step explanation:

Even if there is a transformation, it is asking for the length.

Therefore the length of WZ is 5 units

7 0

2 years ago

Find the product of 0.34 and 0.02

dmitriy555 [2]

Answer:

<h2>The product is 0.68</h2>

Step-by-step explanation:

A product means we are multiplying. we are multiplying 0.34 and 0.02 which is 0.68

6 0

3 years ago

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A measuring wheel is used to calculate the length of a path. The diameter of the wheel is 8 inches. If the wheel rotates 15 time

Oksi-84 [34.3K]

To fint the length first one must find circumference to do that we use the formula D*Pi (diameter times Pi. Diameter = 8 Pi is the constant of 3.1415
so. 8*3.1415 = appox 25.1327. cow that we have circumference we should multiply by the amount of times the wheel rotates (15)
so. 15*251327 = appox 376.9911in now convert to feet. 12 in = 1 foot so divide by 12
so 376.9911 / 12 = about 31.4
round down to 31 feet

8 0

3 years ago

A. Use composition to prove whether or not the functions are inverses of each other. B. Express the domain of the compositions u

Kryger [21]

Given: $f(x) = \frac{1}{x-2}$

$g(x) = \frac{2x+1}{x}$

A.)Consider

$f(g(x))= f(\frac{2x+1}{x} )$

$f(\frac{2x+1}{x} )=\frac{1}{(\frac{2x+1}{x})-2}$

$f(\frac{2x+1}{x} )=\frac{1}{\frac{2x+1-2x}{x}}$

$f(\frac{2x+1}{x} )=\frac{x}{1}$

$f(\frac{2x+1}{x} )=1$

Also,

$g(f(x))= g(\frac{1}{x-2} )$

$g(\frac{1}{x-2} )= \frac{2(\frac{1}{x-2}) +1 }{\frac{1}{x-2}}$

$g(\frac{1}{x-2} )= \frac{\frac{2+x-2}{x-2} }{\frac{1}{x-2}}$

$g(\frac{1}{x-2} )= \frac{x }{1}$

$g(\frac{1}{x-2} )= x$

Since, $f(g(x))=g(f(x))=x$

Therefore, both functions are inverses of each other.

B.

For the Composition function $f(g(x)) = f(\frac{2x+1}{x} )=x$

Since, the function $f(g(x))$ is not defined for $x=0$ .

Therefore, the domain is $(-\infty,0)\cup(0,\infty)$

For the Composition function $g(f(x)) =g(\frac{1}{x-2} )=x$

Since, the function $g(f(x))$ is not defined for $x=2$ .

Therefore, the domain is $(-\infty,2)\cup(2,\infty)$

8 0

3 years ago

Which expression represents "4 less than the product of 2 and a number,<br> e"?

vlabodo [156]

Answer:

2 x e-4

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers