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Elanso [62]
3 years ago
12

NEED HELP ASAP If f(x) = -9x -1 find the dependent variable if the independent value is 2

Mathematics
1 answer:
tensa zangetsu [6.8K]3 years ago
3 0

Answer:

-19

Step-by-step explanation:

plug in 2 for x.

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notsponge [240]

Answer:

57°

Step-by-step explanation:

The angles in a triangle add to 180. Let the missing angle be x.

x=180-90-33=57

6 0
3 years ago
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Which is equivalent to (4xy – 3z)2, and what type of special product is it?
bazaltina [42]
Hello,

Answer D
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le square of the difference of 3z from 4xy.
6 0
3 years ago
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The radius is 10 units, and each layer is one unit high. What is the volume of the cylinder in cubed units?​
alexandr1967 [171]

Answer:

Volume of cylinder is 6285.71 square units.

Step-by-step explanation:

Given the radius of cylinder 10 units. The height is twice its radius. we have to find its volume.

r=10 units

⇒ Diameter, d = 20 units

Also given height is twice its radius.

⇒ Height=2(r)=2(10)=20 units

<h2><em><u>Volume of cylinder=πr^2h</u></em></h2>

= 22/7 × 100×20

=22/7 × 2000

= 44000/7

= 6285.71square units.

hence, volume of cylinder is 6285.71 square units.

6 0
2 years ago
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Solve for x:a(a²+b²)x²+b²x-a​
m_a_m_a [10]

Answer:

x = a/(a² + b²) or x = -1/a  

Step-by-step explanation:

a(a²+ b²)x² + b²x - a =0

Use the quadratic equation formula:

x = \dfrac{-b\pm\sqrt{b^2-4ac}}{2a} =\dfrac{-b\pm\sqrt{D}}{2a}

1. Evaluate the discriminant D

D = b² - 4ac = b⁴ - 4a(a² + b²)(-a) = b⁴ + 4a⁴ + 4a²b²  = (b² + 2a²)²

2. Solve for x

\begin{array}{rcl}x & = & \dfrac{-b\pm\sqrt{D}}{2a}\\\\ & = & \dfrac{-b^{2}\pm\sqrt{(b^{2}+2a^{2})^{2}}}{2a(a^{2} + b^{2})}\\\\ & = & \dfrac{-b^{2}\pm(b^{2}+ 2a^{2})}{2a(a^{2} + b^{2})}\\\\x = \dfrac{-b^{2}+(b^{2} + 2a^{2})}{2a(a^{2} + b^{2})}&\qquad& x =\dfrac{-b^{2}-(b^{2} + 2a^{2})}{2a(a^{2} + b^{2})}\\\\x =\dfrac{-b^{2}+(b^{2} + 2a^{2})}{2a(a^{2} + b^{2})}&\qquad& x =\dfrac{-b^{2}-(b^{2} +2a^{2})}{2a(a^{2} + b^{2})}\\\\\end{array}

\begin{array}{rcl}x = \large \boxed{\mathbf{\dfrac{a}{a^{2} + b^{2}}}}&\qquad& x =\dfrac{-b^{2}-(b^{2} +2a^{2})}{2a(a^{2} + b^{2})}\\\\&\qquad& x =\dfrac{-2b^{2}- 2a^{2}}{2a(a^{2} + b^{2})}\\\\&\qquad& x =\dfrac{-2(a^{2}+ b^{2})}{2a(a^{2} + b^{2})}\\\\&\qquad& x =\large \boxed{\mathbf{-\dfrac{1}{a}}}\\\\\end{array}

5 0
3 years ago
Find the midpoint of the segment with the following endpoints.<br> (1,-10) and (8,-4)
vlada-n [284]

Answer:

(4.5,-7)

Step-by-step explanation:

you add the x coordinates then divide them by 2

And then add the y coordinates then divide them by 2 also

3 0
3 years ago
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