(1) circumference of a circle = 2π.R
(2) area of a circle = π.R²
Area = 452.16 m² (given), so we can calculate the radius:
452.16 = π.R²
452.16/π = R²
143.92 = R² → R =√143.92 ≈ 12 m
Having R = 12, now we can calculate the circumference :
circumference of a circle = 2π.R = 2.π.12 = 75.41 m
<span>A) 2x -5y +z = 1
B) 3 y + 2z = 5
C) -24 z = 48
Those 3 equations you typed were somewhat squished together.
Did I retype those correctly?
Let me know and I'll solve it.
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For a survey like this, you want to take a random sample. It would be a good idea to use an alphabetical list of the students. Then, you could randomly select students from the list.
The principal would want to avoid surveying all the same type of students. For example, don't just ask the athletes.
<span><span><span>Let the original number be "x".
(x-10)/4 = 2
x-10 = 8
x = 18 (original number of pieces of candy.)</span></span></span>
