Answer:
Option D.
Step-by-step explanation:
==>27
r = 3
9r
which means 9x3 = 27.
243log(81x)=48
log(81x)=48÷243
log(81x)=16÷81
81x=10^(16÷81)
81x= 81sqaure root pf 10^16
divide by 81
x =.0194557
By using <span>De Moivre's theorem:
</span>
If we have the complex number ⇒ z = a ( cos θ + i sin θ)
∴
![\sqrt[n]{z} = \sqrt[n]{a} \ (cos \ \frac{\theta + 360K}{n} + i \ sin \ \frac{\theta +360k}{n} )](https://tex.z-dn.net/?f=%20%5Csqrt%5Bn%5D%7Bz%7D%20%3D%20%20%5Csqrt%5Bn%5D%7Ba%7D%20%5C%20%28cos%20%5C%20%20%5Cfrac%7B%5Ctheta%20%2B%20360K%7D%7Bn%7D%20%2B%20i%20%5C%20sin%20%5C%20%5Cfrac%7B%5Ctheta%20%2B360k%7D%7Bn%7D%20%29)
k= 0, 1 , 2, ..... , (n-1)
For The given complex number <span>⇒ z = 81(cos(3π/8) + i sin(3π/8))
</span>
Part (A) <span>
find the modulus for all of the fourth roots </span>
<span>∴ The modulus of the given complex number = l z l = 81
</span>
∴ The modulus of the fourth root =
Part (b) find the angle for each of the four roots
The angle of the given complex number =

There is four roots and the angle between each root =

The angle of the first root =

The angle of the second root =

The angle of the third root =

The angle of the fourth root =
Part (C): find all of the fourth roots of this
The first root =

The second root =

The third root =

The fourth root =
Answer:
The probability of choosing exactly 2 male and 4 female students =
Step-by-step explanation:
We are given that a class has 35 students
Number of male=16
Number of female=19
We have to choose 6 students for committee
We have to find the probability that exactly 2 male students are selected
Probability=P(E)=
If we have to choose total 6 student in which 2 male and 4 female
Combination formula:

Using the formula
The probability of choosing exactly 2 male and 4 female students =
Answer:
x^2-5x+33
Step-by-step explanation:
(x-4)^2 -5x+20-3
x^2-4^2