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garik1379 [7]
3 years ago
5

I need help with this question pls

Mathematics
1 answer:
Marrrta [24]3 years ago
4 0

Answer:

yes

Step-by-step explanation:

yes it is because if 6ounces is $2.10 and the more ounces you add the higher the cost

btw just copy/paste :P

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Tony finishes baking cookies at 10:33 am he started at 7:18 am now long was he baking cookies?
Ber [7]
To find the amount of time between two events, we can use subtraction, just like we do with regular subtraction problems. The subtraction will look something like this:

  10:33
-
  7:18

Like in a regular subtraction problem, we can subtract the digits that line up, like 10 and 7. Subtracting all of the corresponding digits, we get that it took Tony 3 hours and 15 minutes to finish baking the cookies. 
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3 years ago
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Vector question. Let v=<-2,1> u=<3,-5> , find:
lyudmila [28]

Answer:

1. )\vec {v}.\vec{u}= -11

2.) The angle between v and u is 147.52°.

Step-by-step explanation:

Given:

\vec {v}= ( -2 , 1 )\\\vec {u}= ( 3 , -5 )

To Find:

1. \vec {v}.\vec{u}= ?

2.\theta = ?

Solution:

\vec {v}.\vec{u} is scalar product given as,

\vec {v}.\vec{u}=|\vec {v}||\vec {u}|\cos \theta

|\vec {v}|=|(-2, 1)|=\sqrt{(-2)^{2} +1^{2}}=\sqrt{5}\\|\vec {u}|=|(3, 5)|=\sqrt{(3)^{2} +(-5)^{2}}=\sqrt{34}

\vec {v}.\vec{u}=(-2i +j).(3i-5j)\\

Here only i.i = j.j =1 and i.j = j.i = 0

∴ \vec {v}.\vec{u}=(-2\times 3 +1\times -5)\\\vec {v}.\vec{u}=-6-5=-11 \\

Now, Substituting the above values we get

-11=\sqrt{5}\times \sqrt{34}\cos \theta\\ \cos \theta=\frac{-11}{\sqrt{170}} \\ \cos \theta =-0.84366\\\therefore \theta =cos^{-1}(-0.84366)\\\therefore \theta =147.52\°

As it is negative mean \theta is in Second Quadrant Because Cosine is negative in Second Quadrant.

1. )\vec {v}.\vec{u}= -11

2.) The angle between v and u is 147.52°.

5 0
3 years ago
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zimovet [89]

Answer:

(y = mx + b),

8 0
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Where is 23/2 on a number line?
rodikova [14]
23/2 = 11 1/2 or 11.5....its gonna be midway between 11 and 12 on a number line.
6 0
3 years ago
Select the correct answer.
Scilla [17]

Answer:

Approximately (2, 1)

See image

Step-by-step explanation:

Rearrange each equation so it is ready to be graphed on an x-y-axis (see image) look for the point where the two lines cross. This is the solution for the system of equations.

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