Question

A change purse contains an equal number of pennies, nickels, and dimes. the total value of the coins is 512 cents. how many coins of each type does the purse contain?

Answer 1

Let

x---------> the total number of coins

we know that

512 cents-------> is equal to $5.12

1 penny is equal to $0.01

1 nickel is equal to 5 penny--------> $0.05

1 dime is equal to 2 nickel--------> $0.10

$\frac{x}{3}*0.01+ \frac{x}{3}*0.05+\frac{x}{3}*0.10=5.12$

$\frac{x}{3}*[0.01+0.05+0.1]=5.12 \\\\x*[0.16]=15.36 \\\\ x=\frac{15.36}{0.16} \\\\x= 96\ coins$

the total number of coins are 96

Divide 96 by 3 to obtain the number of coins of each type

therefore

the answer is

the number of penny coins are $32$

the number of nickel coins are $32$

the number of dimes coins are $32$